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Working to find the xH2O in salt Taking that quantities of salt solution and acid are expressed in thousandths of a litre, it follows that mol of acid used = 0.0488 x 0.01 = 0.000488 From equation for reaction between acid and salt, Na2CO3 + 2HCl -----> 2NaCl + CO2 + H2O 2 mol of acid reacted with one mole of salt so, mol of salt used = 0.000488/2 = 0.000244 Mol of salt in 1l = 0.000244 x 1000/2.5 = 0.0976 Mass of salt in 1l = 0.0976 x 106g = 10.35g But mass of hydrated salt used was 27.82g So, mass of water in salt = 27.82 - 10.35g = 17.47g Mass ratio of salt to water is 10.35:17.47 Mole ratio of salt to water is 10.35/106:17.47/18 = 0.0976:0.971 or 1:10 dividing by smallest component of ratio therefore moles of water in hydrated salt = 10 Hence formula of salt is Na2CO3.10H2O

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16y ago
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12y ago

0.22 mol/ dm -3

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Q: 27.82 grams of hydrated sodium carbonate crystals was dissolved in water and made up to 1 liter 0.0025 of this solution was neutralized by 0.0488 of hydrochloric acid of concentration 0.01 molar?
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