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According to Newton's second law, Force = mass x acceleration. From the equation F = ma, one can deduce that

A = F/m

Simply plug in the known values and solve.

A = (12 N) / (3kg)

A = 4 m/s^2

The answer is 4 meters per second squared.

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15y ago
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14y ago

Newton's second law of motion

Force causes a mass to acceleerate

Replace the word "causes" with an equal sign and you will have Newton's Second Law of Motion.

Force = Mass * Acceleration

substitute the values of mass and force into this equaton and solve for Acceleration

F = m* a

12N = 3kg * a

a =____ m/s^2

I will let you finish the problem!

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13y ago

Distance = 1/2 (acceleration) x (time)2

Acceleration = (force) / (mass) = 12/3 = 4 m/s2

Distance = 1/2 (4 m/s2) x (5 sec)2 = 2 m/s2 x 25 s2 = 50 meters

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11y ago

8 meters per second

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Q: What acceleration will result when a 12N net force is applied to a 3kg object?
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What affects the acceleration of an object?

An object's acceleration is the result of a force being applied to it. When that happens, the magnitude of the resulting acceleration is equal to the force divided by the object's mass, and the direction of the acceleration is in the direction of the force.


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Acceleration increases as force increases.


What acceleration will result when a 12N net force applied to 3kg and a 6kg object?

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Yes, increased force applied to an object results in an increase in acceleration.


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Object shows acceleration when the force applied on it is increased.


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Newtons 2nd law means that when force is applied on any object an acceleration is produced in the direction of force which is applied on it. The acceleration produced in the object is directly proportional to the force applied on the object i.e. if force increases then acceleration will also increase and the acceleration is inversely proportional to the mass of object i.e. if the mass of the body decreases then acceleration will increase. If force is represented by 'F', acceleration by 'a' and mass by 'm' then a is directly proportional to F a is inversely proportional to m


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What acceleration will result when a 12N net fore applied to a 3 kg object?

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