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At 45 degrees.

Yay! I got a proof done, check the link below, back to studying derivations for a infinite line of charge, ewww.

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Q: A ball is thrown with a velocity of 40 meters per second at an angle above the horizontal. If the ball attains its maximum range what was the value of the angle?
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If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?

If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.


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When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what will be it maximum height?

'Maximum height' means the exact point at which the velocity changes from upward to downward. At that exact point, the magnitude of the velocity is zero. It doesn't matter what the velocity was when it left your hand. That number determines the maximum height, but the velocity at that height is always zero. --------------------------------------------------------- Thus using the formula: (vf)e2 = (vi)e2+2*a*d vf = final velocity = 0 m/s vi = initial velocity = 10 m/s a = acceleration = gravity = - 9.81 m/s/s d = displacement (distance) = ? e is designating that the next figure is an exponent in the formula So the formula is: (0)e2 = (10)e2 + (2 * -9.81 * d) 0 = 100 + -19.62d adding 19.62d to both sides of the equation 19.62d = 100 dividing by 19.62 d = ~ 5.097 meters


An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?

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If a slide went vertical for 100 meters then horizontal for 10 and vertical again for another 90 meters would you survive or be flung off at the 10 meter horizontal?

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Related questions

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The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.


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The maximum velocity of a ball as it drops is 12 meters per second. The maximum velocity of the ball after the first bounce is -6 meters per second. What is the difference between the two velocities?

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A ball is thrown from the ground into the air at a height of 9.1 m the velocity is observed to be v7.6i 6.1j in meters per second x axis horizontal y axis vertical and up a to what maximum h?

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It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.


What is acceleration at instantaneous maximum velocity?

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What is the average acceleration of car if it travels in a straight line in one minute and it attains a velocity of 40 meters second second and it finally?

There is not enough information to answer the question. The initial velocity of the car is not given. Also, the "it finally" at the end of the question does not make sense.


How does the unbalanced force of gravity affect the horizontal and vertical velocity of an object in projectile?

In the absence of air resistance, the force of gravity has no effect on the horizontal component of a projectile's velocity, and causes the vertical component of its velocity to increase by 9.8 meters (32.2 feet) per second downward for every second of its flight.


If the launch angle is 15 degrees and the initial velocity is 50.0 meters per second what is the range?

If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.