A photon of wavelength 3000 A is absorbed by a gas and remitted as two photons One of the photons is red 7600 A What is the wavelength of the other photon?

Photon Energy E=hf = hc/w thus wavelength w= hc/E or the wavelength is hc divided by the energy of the photon or w= .2 e-24 Joule meter/Photon Energy.

p=h/lambda so lambda=h/p but E=hf=hc/lambda so lambda=hc/E hence lambda=hc/E relates wavelength (lambda) to the energy of a photon

Visible radiation: 370-750 nm. Infrared radiation: 750 nm-300 μm These wavelenghts are not long.

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