well for a starters, "r" is obviously recessive as you didnt use any upper case lettering. if both flowers have homozygous recessive (homo being same) genes, then, with the use of a PUNNET SQUARE, you would be able to work out that any offspring that the flowers will have, will also have homozygous recessive genes (white).
so.. sort of like this...
Mother
r r
F
a r rr rr
t
h r rr rr
e
r
sorry if its kinda hard to understand :P lol. otherwise search up punnet sqaures. helped me a lot. :P
75% red; 25% white
It Depends If The Red Flower Is Dominant then it should Be RR but if its Recessive then its rr so depending on the F1 you should know the Genotype of The Red FLower.
Rr X Rr = 1RR, 2 Rr, and 1rr
A trait that exhibits incomplete dominance, is one in which the heterozygous offspring will have a phenotype that is a blend between the two parent organisms. An example of this is when a homozygous red sweet pea flower crossed with a homozygous white sweet pea flower, their offspring will be heterozygous and have the pink phenotype, rather than either red or white.
Assuming that white is recessive to red in this case, then the off spring would all be red but they would be heterozygous red (Rr).
Let us assume that both Rr and rr produce red flowers and only rr produces white flowers. Since one parents and the offspring are white, they have rr as genotypes. In order to achieve this result, the other parent would have to haev at least one r in its genotype. Since the otehr parent is red and needs to have one r, it's genotype is Rr. In short, the parents's genotypes are Rr for the red one and rr for the white one.
It Depends If The Red Flower Is Dominant then it should Be RR but if its Recessive then its rr so depending on the F1 you should know the Genotype of The Red FLower.
The backcross between a heterozygous (monohybrid) red flower plant (Rr) and a homozygous recessive white flower plant (rr) would produce a ratio of 1Rr:1rr. So you would expect half of the offspring to be red (Rr) and half the offspring to be white (rr).
Rr X Rr = 1RR, 2 Rr, and 1rr
incomplete dominance
A trait that exhibits incomplete dominance, is one in which the heterozygous offspring will have a phenotype that is a blend between the two parent organisms. An example of this is when a homozygous red sweet pea flower crossed with a homozygous white sweet pea flower, their offspring will be heterozygous and have the pink phenotype, rather than either red or white.
The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).The red color is RR and pink is Rr. RR is red, rr is white and Rr is pink. Cross the two: RR (red) and Rr (pink). You will get RR and Rr in a 1:1 ratio. You will not get any rr (white).
1:2:1
Assuming that white is recessive to red in this case, then the off spring would all be red but they would be heterozygous red (Rr).
If red color is dominant, (RR) and white is recessive, (rr) then crossing a homozygous red plant with a homozygous white plant will produce 100% red offspring. This is the F1 generation. These F1 offspring will be 100% heterozygous (Rr). Subsequent crosses of these offspring in the second generation (F2) will produce 75% red and 25% white offspring phenotypically (the visual appearance of the color, The genotype ratio will 1 RR: 2 Rr:1rr with percentages of 25% homozygous red 50% heterozygous red and 25% homozygous white.
Let us assume that both Rr and rr produce red flowers and only rr produces white flowers. Since one parents and the offspring are white, they have rr as genotypes. In order to achieve this result, the other parent would have to haev at least one r in its genotype. Since the otehr parent is red and needs to have one r, it's genotype is Rr. In short, the parents's genotypes are Rr for the red one and rr for the white one.
Plato users, Heterozygous (Rr), red.
Let's say we're talking about red flowers (red=dominant, R allele) vs white flowers (white=recessive, r allele) If you cross two homozygous red flowers, RR x RR, you can only get RR offspring, or all red flowers. RR=genotype (what alleles, or genes, they have), red=phenotype (what they look like) To make the Punnett square, draw a 4-box diagram on a piece of paper by drawing a diagonal line and then a horizontal line halfway down so you get 4 squares. On the top of the box, put R R and along the left side, put R and then another R under it. To fill in the boxes for the Punnett square, cross the top left-hand gene (R) with the top gene on the left-hand side. You'll get RR. Do the same for the top right-hand gene (R) and the top gene on the side. You'll also get RR. Cross the bottom R with the left gene on the top (R) and the right gene on the top. All combinations will be RR in this example. If you had a red flower that had a homozygous genotype (RR) with a white flower, also homozygous (rr), the results are more interesting. When you draw your Punnett square, you'll see that you get one RR combination, two Rr combinations and one rr combination. This means that the F1 generation (offspring) will be: 25% homozygous red (RR) 50% heterozygous red (Rr) 25% homozygous white (rr) Put another way, you'll have one white flower and three red flowers, and two of those red flowers carry a gene for white which is not expressed because it is recessive.