one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
If a fixed sample of gas has a change of temperature pressure would increase.
Determine the specific heat of a material if a 32 g sample of the material absorbs 58 J as it is heated from 298 K to 313 K?
Calorimetry measures the heat of chemical reactions and physical changes. The steps involved in solving calorimetry problems are as follows: The heat of the reaction is less than the amount of heat measured by the calometer. The heat gained by the calometer is the capacity of the calorimeter and temperature change of the sample undergoing the chemical and/or physical change. The combination of the two are calculated to heat reaction and given temperature change.
It is doubtful that the walls of the sample holder in the calorimeter start at the same temperature as the sample. By stirring it, you can help equalize the temperature throughout the sample and bring the sample and the sample holder into thermal equilibrium before you start the measurements.
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When a sample of a substance absorbs thermal energy, its temperature rises.
If a fixed sample of gas has a change of temperature pressure would increase.
Determine the specific heat of a material if a 32 g sample of the material absorbs 58 J as it is heated from 298 K to 313 K?
80
80 calories per gram
38 cal
changes 10 degrees C and 283 degrees K if im not mistaken which im bound to be not sure of the esential #
Calorimetry measures the heat of chemical reactions and physical changes. The steps involved in solving calorimetry problems are as follows: The heat of the reaction is less than the amount of heat measured by the calometer. The heat gained by the calometer is the capacity of the calorimeter and temperature change of the sample undergoing the chemical and/or physical change. The combination of the two are calculated to heat reaction and given temperature change.
Because they are the same temperature. There are more calories of heat in a 100-ml sample of water that's at a certain temperature than there are in a 10-ml sample that's the same temperature...but 20-degree-Celsius water is 20-degree-Celsius water whether you have a thimbleful, a glassful or a swimming pool full.
The difference between the temperature at which the sample begins to melt and at the temperature at which the sample completely melted-
That would depend on the mass of the sample, its temperature, and what the sample is made of.
The needed heat is:Q = 10 x 20 x 0,031 = 6,2 calories