Here is the balanced chemical equation, producing the right compounds of NO2 and H20:
Cu + 4HNO3 --> Cu(NO3)2 + 2NO2 + 2H2O
CuS + 4HNO3 --> Cu(NO3)2 + S + 2NO2 + 2H2O
Cu + 2 H2SO4 ---> CuSO4 + SO2 + 2 H2O
Copper + Sulphuric Acid ---> Copper Sulphate + Sulphur Dioxide + Water
Cu(NO3)2 + 2NaOH = Cu (OH)2 + 2NaNO3
H2S + Cu(NO3)2 >> CuS + 2HNO3
Cu(NO3)2 + 2NaOH >> Cu(OH)2 + 2NaNO3
If the copper nitrate formed is copper (I) nitrate, the equation balances with one atom of each metal and one formula weight of each nitrate. If the copper nitrate formed is copper (II) nitrate, the balanced equation is: 2 AgNO3 + Cu -> 2 Ag + Cu(NO3)2.
Cu (OH)2 = CuO2 + H2O
Copper(II) hydroxide and sodium nitrate are thermally decomposed to oxides by heating.
When heat copper hydroxide and sodium Nitrate the pale blue precipitate change into black solid
One balanced equation for the reaction between elemental copper and silver nitrate is Cu + AgNO3 -> CuNO3 + Ag.
No reaction
Your balanced chemical equation for this double replacement reaction would be: Cu(NO3)2 + 2KOH ----> Cu(OH)2 + 2KNO3 Therefore, you would end up with copper II hydroxide and potassium nitrate.
Cu(NO3)2 + 2NaOH >> Cu(OH)2 + 2NaNO3
No. It is a chemical change (chemical reaction) in which the products are different from the reactants. The balanced chemical equation is Cu(NO3)2+2NH4OH-->Cu(OH)2+2NH4NO3, which means one mole of copper(II) nitrate plus two moles of ammonium hydroxide produce one mole of copper(II) hydroxide plus two moles of ammonium nitrate.
If the copper nitrate formed is copper (I) nitrate, the equation balances with one atom of each metal and one formula weight of each nitrate. If the copper nitrate formed is copper (II) nitrate, the balanced equation is: 2 AgNO3 + Cu -> 2 Ag + Cu(NO3)2.
The balanced equation is Cu(OH)2 (s) (heat) = CuO + H2O.
The compound copper (III) chloride doesn't exist !
Cu (OH)2 = CuO2 + H2O
The products are Sodium Nitrate and Copper Hydroxide.
CuSOβ+2NaOH=NaβSOβ+Cu(OH)ββ
This is a double-replacement reaction. The charges of each cation and anion are:Copper (II): 2+Nitrate: 1-Sodium: 1+Hydroxide: 1-This means that the equation without coefficients would beCu(NO3)2 + NaOH --> NaNO3 + Cu(OH)2.Since there is an uneven number of nitrates and hydroxides, coefficients must be added before NaOH and NaNO3 to make the equation balanced.Cu(NO3)2 + 2NaOH --> 2NaNO3 + Cu(OH)2