Here is a simple program to generate prime numbers upto a given specific number
/*Prime No. from 1 to 50*/
/*By-Himanshu Rathee*/
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,n;
clrscr();
printf(" Enter the number upto which we have to find the prime number: ");
scanf("%d",&n);
printf("\n");
for(i=2;i<=n;i++)
{
for(j=2;j<=i-1;j++)
if(i%j==0)
break;
/*Number is divisble by some other number. So break out*/
if(i==j)
printf("\t%d",i);
/*Number was divisible by itself (that is, i was same as j)*/
}
/*Continue loop upto nth number*/
getch();
}
#include <iostream>
#include <math.h>
using namespace std;
int knum;
int i = 1;
int pt = 0;
bool is_prime;
int main()
{
cout << endl << endl;
cout << "This Program calulates the prime numbers between" << endl;
cout << "a given start and end number.";
start: cout << endl << endl << "Please enter a starting number (enter 0 to exit): ";
cin >> i;
if (i 0)
is_prime = false;
}// only when the "for" cycle is done we know for sure if "i" is prime
if (is_prime)
cout << i << ", ";
i++;
}
goto start;
close: cin.get();
return 0;
system("pause");
}
look man that would take alot >>> Ill give you the way =============================================================================== this answer i write it now on net ! i read about that befor in it uni where i study i will chick out the answer and re write it best wishes 2024
PRINT 2,3,5,7,11,13,17,19,23,29,31,37
Loop through some numbers - for example, 2 through 100 - and check each one whether it is a prime number (write a second loop to test whether it is divisible by any number between 2 and the number minus 1). If, in this second loop, you find a factor that is greater than 1 and less than the number, it is not a prime, and you can print it out.
I am providing a succinct and easy to understand version of the program. I have run it in 3-4 compilers and it works perfect. Mind you, you should not enter a number more than 2147483647 (which is the largest number a variable can process in C!). If you do, no problem, but it will display all numbers above it, including the even numbers to be prime. So here you are:#include#includemain(){long int a,b,c;printf("Enter the number: ");scanf("%ld",&a);for (b=2;b
(defun prime (num) (if (< 2 num) (do ((dividend 2 (1 + dividend)) (chk-to (sqrt num))) ((equal (rem num dividend) 0)) (when (<= chk-to dividend) (return t))) t))
VBnet program to find the prime numbers between 100 to 200?
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Prime numbers are numbers that are only divisible by themselves and the number 1. You can write a program to print all prime numbers from 1 to 100 in FoxPro.
Since there is an infinite set of prime numbers the answer would be infinity.
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By learning how to program on C+.
program to find prime number in 8085 microprocessor
Write a function that implements an algorithm that checks to see if a particular integer is prime (returning a boolean). Write a program that uses that function on each number from 1 to 100, and if true, displays that number.
You really need some nested loops; but some programming languages might allow you to write this as one statement.
This would require some computer knowledge. It can make it easier to find out the prime numbers without figuring it out in your head.
37, 41, and 43
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