molarity = mol / litre The concentration is 10% HCl in water, assuming this is expressed in w/v (weight to volume) as this is the normal way. The density of 10% HCl is unknown but will be estimated to be the same as water (although slightly incorrect), since no data is given. 1 L of which 10% are HCl is assumed to weigh 1000 grams. 10% HCl x 1000g = 100g of HCl. 100g of HCl is present in 1 L. The mw of HCl = 36.5g/mol, 100g/(36.5g/mol) = 2.74mol is present in 1 L. The molarity is 2.74mol / 1 L = 2.7 M (two significant figures) (Looking up hydrochloric acid in wikipedia tells us that the density of a 10% solution is actually 1048g/L and the actual molarity becomes 2.87M. The calculated number was close enough, but it shows that the density is important. Molality on the other hand is mol/kg, so with molality we can skip the unknown density problem. For practical purposes, molarity is still the mostly used one, because volume is easier to measure than weight in the laboratory when handling toxic solvents that are unhealthy to inhale.)
6M
molarity of 5% NaCl solution would be 1.25M.
17 M
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.
Formalin is 40% solution of formaldehyde not an acid.
The mole fraction of HCl in 20 percent aqueous solution is 0.21.
6M
molarity of 5% NaCl solution would be 1.25M.
17 M
5.84 M
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.
approximalety 2.94 molar
Formalin is 40% solution of formaldehyde not an acid.
Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.
How to work it out - Calculate the concentration of the solution in terms of molarity. Calculate the hydrogen ion concentration from the fact that multiplying the hydrogen and hydroxide concentrations (in mols per litre) will always give 1x10-14. Take the -log10 of the hydrogen ion concentration.
100 g of solution containing 50 g of NaOH.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)