Before HNO3 addition [HA]= 6.0 mmol NH4+ in 100 ml => after: [HA]= 6.0+5.3 mmol NH4+ in 101 ml
Before HNO3 addition [A]= 11.5 mmol NH3 in 100 ml => after: [HA]= 11.5-5.3 mmol NH3 in 101 ml
Thus: (notice that pH of buffer is independent from a large range of dilution)
pHbefore = 9.24- log10(6.0/100 / 11.5/100) = 9.24 - log10(6/11.5) = 9.52
and:
pHafter = 9.24 - log10(11.3/101 / 6.2/101) = 9.24 - log10(11.3/6.2) = 8.98
NH4Cl,sol --> NH3,gas + HCl,gas
Basically you have 0.43 mol of NH4Cl. In NH4Cl there are two ions, NH+ and Cl-. You set up the problem as: 0.43 mol of NH4Cl X (2 mol ions/ 1 mol of NH4Cl) = 0.86 mol ions
2 NH4Cl +Mg(OH)2 -> 2 NH4OH + MgCl2
53.491g
Green.
The compound NH4Cl contains one ammonium ion for each chloride ion. Based on the naming rules for ionic compounds, this compound is simply ammonium chloride. Note that NH4 should not be confused with NH3, which is ammonia and is not an ion.
More Cl- is being excreted as Nh4Cl to buffer the excess acid in the renal tubules, leaving less Cl- in the Extracellular Fluid
NH4Cl-------------ammonium chloride
NH4Cl is not binary.
Ammonium chloride is an inorganic compound also called NH4Cl.
this is buffer system consisted of a weak base and its conjugated base. NH4OH is the weak acid and the NH4Cl is the conjugated base. when an acid or a base is added in small amount the change of the pH of this solution is neglegible hence we tells that this shows a resistivity when adding an acid or a base .when an acid is added OH ions reacts and form H2O and NH4OH dissociates and give the OH ions to the solution .When an base is added NH+ ions react with OH ions added and form NH4OH which dissociates weakly to NH+ ions and OH- ions .
- log(0.001 M NH4Cl) = 3 pH =====
NH4Cl,sol --> NH3,gas + HCl,gas
NH4Cl is ammonium chloride.
No. NH4Cl is a salt, though it is weakly acidic.
the bond in NH4Cl is somewhat ionic because NH4 is positive and CL is negative
Ammonium Chloride! Hope this helps! :)