Can a 9 volt battery charger be used to charge a 9.6 V battery pack?

Question/Answer

I wouldnt really say it is just impossible to charge a 9.6 volt battery using a 9V supply. I'm currently researching a way to charge a 1 V battery using 20-30mv supply. This would help charging batteries solely by environmental noise. Reasearchers HAVE devised chargers that are able to do this, though as of now, this is possible only for 1V capacitances.

Answer

Combining the information provided in the answers that say "no" leads you to the conclusiion that yes, it should work - slowly. As pointed out in one answer, a battery charger produces a little more voltage than the battery it's charging. A 9V charger produces roughly 10-11 volts depending on the type of charger. (Regular, "smart", or PWM). A 10-11 volt current from a 9V charger WILL charge a 9.6V battery pack. It'll just take a lot longer than charging a 9V battery. Most of the available power in the pack is in the last .6 volts, so you'll want to leave it long enough to charge all the way to 9.6V.

Answer

Most likely, but a battery pack is usually modified to produce a specific amount of amps. This may affect the battery pack. Also, make sure the battery specs are identical. NiCd is a common rechargable battery type. It is a dangerous thing to try. Wear your saftey goggles or perhaps a welding mask. If it gets hot quickly, either run or immediately remove it!

Answer

The simple answer is NO.

It is possible to charge a 9.6V battery pack with 9V only to a maximum of 9V. That is, a battery as low as 6V could charged up to 9V.

I think that you are trying to recharge an NiMH or NiCD battery pack. Both these have a 1.2v per cell, that is you have 8 cells to get to 9.6V. Usually 9.6V cells are used to run 9V equipment, so it won't matter much. But in the case of heavy duty applications, typically that of cordless powertools, it will effect performance severely if you could onle get 9V out of it. Most tools and equipment will still operate with batteries as low as 6V, but then you are really pushing it.

Always remember that Power (P) = Volts (V) * Current (I) thus P=V*I. If power is constant as in powertool, and the voltage goes down, The current must go up. That current comes from the battery. Batteries have their own maximum current it could supply, if you exeed that limit, your device's power will drop. Thus lets say you need 100Watts of Power from a 9.6V battery. If P=V*I then I=P/V, I=100/9.6, I=10.41Amps Now your battery sits at 9V, thus I=100/9 then I=11.11 Amps. As you can see you need more current as the voltage drops, this extra current will in turn cause the voltage to drop even more, and before you know it, you screwdriver slows down as the maximum current that the battery can deliver is now reached.

Some replies lower down, mention that the batteries need to be same specification if you want to recharge. Not true. If you recharge a lets 1000mAh battery with 1000mAh, you will and up with two batteries that in theory only contains 500mAh of charge each. In practice you will be lucky to end with 400mAh each due to losses. Think of battery charge as a bottle of water. You can fill up a smaller bottle with a larger bottle, not the other way round.

For that reason a 12V car battery which eaily contains 60000mAh of charge, can easily charge a 2000mAh battery of any voltage below about 12.6V (Car batteries have 6 cells of 2.1V each) but you have to limit the power and current to the batteries under charge, or else you will have the "explosion" as mentioned above! Don't even briefly touch any rechargeable battery to a car battery without at least a resistor in between.

It is an extremely simple circuit needed to charge a lower voltage battery from a higher voltage battery, but remember, a 2000mAh 12V battery have no chance in hell of recharging a 1200mAh 9.6V battery, remember the water bottle? Yes there is 800mAh "spare" but by the time you reach that point, the donor batterie's voltage would have dropped more than the recipient's, as I mentioned in the above formula. You would have a battery of at least 4 times the discharged batteries capacity. Please bear in mind that it seldom happens that a battery is completely discharged at the start of the charging cycle, so it *may* be possible. Remember, a half empty bottle, need only half its volume to be filled.

Answer

This will not work. In order to charge a battery, you need to apply a slightly higher voltage than the battery is rated at, or no charge current will flow. I imagine 9.6 volt charger would supply over 10 volts. Just as in an automobile. Your car's alternator charges your 12v battery with 13.6 volts.

Answer

You will need a power supply of some sort that can produce a voltage greater than the battery that you are trying to charge. The power supply should have a current rating great enough to provide a sufficient charging current without overheating. You should also ensure that the charging current is not so great as to damage the battery, either by overheating it, or by overcharging it. The output voltage of the charger should probably only be several tenths of a volt greater than the battery pack. A resistance in series will help to limit the charging current.

Answer

A good rule of thumb is approximately 11% greater voltage power to recharge. meaning if you intend to recharge lets say a 100V battery (just for numbers sake), it would be best to use a 111V or greater...... or 50V would need about a 62V 10V would require about an 11/12 V recharge. so on and so forth

Answer

I cannot say yes. Batteries have an mAh rating which indicates how long the battery lasts. If a battery is rated at 200 mAh, you can use 200mA from it for one hour before it completely dies. You can think of charging batteries the same way. You can give them current. If you connect a resistor, a lamp, and a battery in a loop, you can calculate the current using Current=voltage / resistance.

A respondant above mentioned the equation for power which is very useful.

Answer

Basically, no. If you mean the chargers for 9V rechargable batteries charging a 9.6V remote control car battery, it will not work. It's easier to just buy the proper charger. Also, voltage alone is not a measure of whether the charger will work. If you're still unsure, post mA values for both.

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