yeah of-course..... for DC circuit holds good...:)
Ohms measure electrical resistance. The resistance in ohms is the voltage divided by the current.
ohms is a measure of resistance(R) in a circuit. Watts is a measure of the power(P), in this case lets assume it is the power used by the resistive element (lamp, heater etc). Power(watts)=Current(Amps)x Current(amps) x Resistance(ohms) or Resistance (ohms)=Power(W)/(current x current)
Ohms are used to measure electric resistance.
Ohm's Law: Resistance is voltage divided by current 110 volts divided by 0.4 amperes is 275 ohms.
Amps, or amperes, are a measure of electrical current; ohms are a measure of electrical resistance. Both are widely used in physics.
ohm
Light Emitting Diodes (LED) solid state devices are current dependant. LED have ratings for the max current allowed to the LED device. A typical current allowed to a LED is 20ma. Ohms Law is used to determine the resistance required to limit the current to your desired current. The formula is used in this manner: E=12VOLTS the desired current is I = 20ma. R = E/I = 600 ohms. Where E=2 volts dc and I=20ma R= E/I = 100 Ohms.
Your question is incomplete. What you meant to say is "What is the voltage drop of a 1.2K Ohm resistance?" (an Ohm is a unit of measurement, a resistor or resistance is measured in ohms.) The answer is, it depends on the current flowing through the circuit. Use the formula V=IR where V is the voltage, I is the current in amps, and R is the resistance in ohms.
They are the three components that are used in Ohms law. Knowing any two will lead to the calculation of the third.
The power used, assuming Unity Power Factor (resistive load), is the product of resistance and the square of the current -- or 1210 Watts.
Ohms are the unit of resistance you find in Ohms LAw which says Volts = Amps x Ohms. You can get a voltage drop across a resistance, but would have to know what current is being used and you would have a potentiometer in effect. You are not "converting 12V" to 10V, your are essentially loosing two volts through a resistor.
A current shunt is a device with a very low resistance, usually around one ohm. The exact resistance of the shunt is printed on the device for reference, and it is often slightly higher or lower than nominal, for example a 1 ohm shunt may actually have a resistance of .99986 ohms or 1.0002 ohms. A current shunt is not used to control current, however, so I do not know if this is the device you are asking about. It is used to measure current by using a precision voltmeter to measure the voltage drop across the shunt, and then using ohms law to calculate the current. Voltage (Volts) divided by Resistance (Ohms) equals Current (Amps). When the shunt is placed so that it interrupts a circuit, (placed in series), the current flowing in the circuit can be accurately measured with the shunt, without changing the values in the circuit enough to affect it. Many shunts of this type have a large heavy duty resistor that does not overheat easily. The shunt should also have a max current rating listed on it.