Can you guarantee that it is always possible to choose three numbers that will add up to a multiple of three from any set of five positive whole numbers?
EVERY three consecutive numbers add to a multiple of 3:Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1)This means that for any three consecutive numbers, the total is 3 times...
Yes. Here's why... What we need to do is find five numbers out of which a combination of three can not be picked whose sum is divisible by three. The easiest way to see whether or not that's possible...