E= ezc/4pi r^2, the same as an electron but positive.
Please refer to the related link for a image of a point charge at (0,0) and the small effect of a point charge a distance away.
Upward.
The magnitude of the electric field is 2.5.
among such particles are electro , proton , positron , betatron an quarks.... APEX: Neutron
First off you know that when it says "Proton" you should know that its a Positive (+) Charged subatomic particle! Now You use the equation that says --> Volt = Electric Potential Energy / Q Volt = 0.5 / +1 (proton) Volt = 0.5
Force experienced will be same in magnitude as that of electron but in opp direction i.e. F=qE.
A proton has a positive electrical charge and an electron has a negative electrical charge.
A 'gravitational field' and an 'electric field' surrounds every proton.
The magnitude of the electric field is 2.5.
The magnitude of the electric field is 2.5.
The 'direction' of the electrostatic (E) field is defined as the direction of the force on a positive charge in the field. The proton carries a positive charge, so when immersed in the E field directed from left to right, there is a force on the proton directed toward the right, and if you let go of the proton, it will go shooting off to the right.
yes, it has less mass.
among such particles are electro , proton , positron , betatron an quarks.... APEX: Neutron
The proton will have greater acceleration. This is because the proton has a higher charge to mass ratio than the alpha particle. The proton has a +1 charge, as you know, and the alpha particle has a +2 charge because it has 2 protons in it. But the alpha particle also has a pair of neutrons fuesed to those 2 protons, so it has a 2 to 4 charge to mass ratio. The proton, with its 1 to 1 ratio of charge to mass, will have a greater acceleration in the same electric field.
First off you know that when it says "Proton" you should know that its a Positive (+) Charged subatomic particle! Now You use the equation that says --> Volt = Electric Potential Energy / Q Volt = 0.5 / +1 (proton) Volt = 0.5
Yes. The proton field is E = d/dr ezc/2r = -ezc/2r2 .
Force experienced will be same in magnitude as that of electron but in opp direction i.e. F=qE.
No. Electric charges are generally electrons.
Positive