Yes, the weight of an object changes when it is underwater. Although its mass does not change under water, its weight does change because of buoyancy. Objects weigh less under water, even ones that sink. Consider how you feel when you're in a pool up to your neck. You feel almost weightless. That's because water is "pushing up" on you with a force equal to the force gravity pulls down on the mass of water your body displaces when in the water. The "pushing up" is the force of the water acting on you, and we call that buoyancy. Notice that your mass did not change at all through this. Your mass is the same as it was before you went into the water.
Yes.
Weight is a force calculated with the formula
F = m x g;
where m is the mass of the object and g is the gravitational acceleration and has a value of about 9.81, varying on where you are on the planet.
The mass is the same, but because of Archimede's Effect which states that the force with which an object is pushed out of a liquid is equal to the mass of liquid it replaces.
There is a formula for this too, but that is out of the scope of the question.
.
get the volume of that object in square meter, multiply it by 1000 and then decrees this no from the weight of the object in kilograms.
If answer is negetive then weight will be zero.
An example is that the weight of a whale is supported by the water in which it swims. Without this support, the weight of the whale would cause the whale's internal organs and lungs to become compressed, and the whale would die.
The weight doesn't change. The apparent weight will be reduced by the amount of displaced water (volume of the displaced water, multiplied by its density), since the water pushes the object up by this amount.
No. Water is denser than air. Wen objects are under water there is more pressure on them this pressure causes the object to wna go up a bit which reduces the force of gravity
The apparent weight decreases, because of the buoyant force (upwards push) provided by the water.
It appears to decrease.
it doesnt
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
because water weighs more than air, and there for, the weight difference between the water + object is less, making it seem as if the object has a smaller mass. Eg. Air = 0 (because we cant weigh it, so we set it as neutral) Water = 25 Object = 100 Object out of water = 100 Object in water = 75. Making it seem lighter
This phenomenon is called buoyancy and is caused by the object displacing water equal to its volume. If the weight of the object is less than the weight of this displaced water, then the object has positive buoyancy and will float. If the weight of the object is exactly equal to the weight of this displaced water, then the object has neutral buoyancy and thus be weightless. If the weight of the object is greater than the weight of this displaced water, then the object has negative buoyancy and will sink but it still weighs less than it did out of the water.Just remember buoyancy only affects the weight of the object, it has no effect on the mass of the object which remains constant in or out of water.
The mass of an object does not change , but its weight can vary.
Here's one way that would work: 1. Weigh a bowl of water. 2. Hold the object underwater with a piece of wire or straw and mark the higher water level with a grease marker. 3. Fill the bowl to the line with more water and weigh it again.
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
because water weighs more than air, and there for, the weight difference between the water + object is less, making it seem as if the object has a smaller mass. Eg. Air = 0 (because we cant weigh it, so we set it as neutral) Water = 25 Object = 100 Object out of water = 100 Object in water = 75. Making it seem lighter
Yes, when the object is submerged in water then water exerts opposite buoyonci force which decrease the weight of object.
The water around floating object's is a measure of that object's "Displacement". For the object to float the weight of displacement must equal the object's weight. If the water around an object is of a greater weight than an object's displacement, then the object will sink.
The difference between an object's weight, and the weight of water with the same volume as the object.
The mass of an object does not change , but its weight can vary.
Archimedes principle states that : The force of buoyancy is equal to the weight of the displaced water. If the weight of the water displaced is less than the weight of the object , the object will sink. Otherwise the object will float , with the weight of the water displace equal to the weight of the object.
This phenomenon is called buoyancy and is caused by the object displacing water equal to its volume. If the weight of the object is less than the weight of this displaced water, then the object has positive buoyancy and will float. If the weight of the object is exactly equal to the weight of this displaced water, then the object has neutral buoyancy and thus be weightless. If the weight of the object is greater than the weight of this displaced water, then the object has negative buoyancy and will sink but it still weighs less than it did out of the water.Just remember buoyancy only affects the weight of the object, it has no effect on the mass of the object which remains constant in or out of water.
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
Such an object's mass would not change, or it wouldn't change significantly. Its weight will be reduced, approximately by a factor of 6.
The force of Buoyancy in water subtracts from the weight of the object in air.
No. The mass of an object doesn't change (Law of Conservation of Mass), therefore its weight won't change either (weight = mass x gravity).