NaOH + H2O ---> Na+(aq) + OH-(aq) + H2O
or in Net Ionic terms
NaOH ----> Na+(aq) + OH-(aq)
There is no reaction. NaOH only ionizes.
2Na(s) + 2H2O --> 2NaOH(aq) + H2(g) may be written in words as sodium plus water gives sodium hydroxide plus hydrogen.
Two moles of solid sodium reacts with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas.
2Na+2H2o=2NaOH+H2
2(Na) + 2(H2O) --> 2 (NaOH) + (H2)
Na + 2H2O ----> 2NaOH + H2
2Na + 2H2O -> 2NaOH + H2
6na +6h2o = 6naoh + 3h2
Na2O + H2O ---------> 2NaOH
This reaction gives ammonium chloride as the product.
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
Reversing the equation gives the oxidation half reaction. Doing this changes the sign on the voltage, not the magnitude.
Potassium plus Water gives Potassium Hydroxide plus Hydrogen
Na2O + H2O ---------> 2NaOH
This reaction gives ammonium chloride as the product.
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
There's two possible reactions Zink with solid NaOH gives double salt Zn + 2NaOH --t--> Na2ZnO2 + H2 And I Think you need the other one: Zink with NaOH(aq) gives the complex salt: Zn + 2NaOH + 2H2O --> Na2[Zn(OH)4] + H2
The reaction equation gives the RATIO of moles reactant to moles product. With known molar mass the (mass) yield can be calculated. (Of course other reactants are to be in excess! for complete reaction of the reactant involved for this yield)
It sort of means 'equals', but more correctly means 'gives' or 'produces'
the coefficients of a balanced reaction
what are the products of the reaction between aluminum chloride and cesium
a mole ratio of any two substances in the reaction
Reversing the equation gives the oxidation half reaction. Doing this changes the sign on the voltage, not the magnitude.
Reversing the equation gives the oxidation half reaction. Doing this changes the sign on the voltage, not the magnitude.
Potassium plus Water gives Potassium Hydroxide plus Hydrogen