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Explain pre increment and post increment operator with an example?

In: C Programming [Edit categories]

Answer:

include<stdio.h>
main()

{
int b=5;
int c= (b++) + (++b) + (++b) + (++b);
printf("%d",c);
}

Ans: The answer will be 29.

because
1st the value of b is 5

so in 1st b++ it will be 5(then will increment to 6)

so in 2nd ++b it will increment(b=6) value to 7.

and in 3rd ++b it will be 8

and in 4th ++b it will be 9

thus the final answer is 5+7+8+9=29...
-----

Although the above answer is correct but the approach is wrong i guess:
If you proceed according to your solution:
what will be the output for this:

x=5
y=++x * ++x;
printf("x=%d and y=%d",x,y);

?

Regards.

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Contributor:

Techsavy.ravi

First answer by ID2057791058. Last edit by Bagulsagar3790. Contributor trust: 0 [recommend contributor ]. Question popularity: 8 [recommend question].

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FAQ: Why do some people think x = ++y + y++ is bad?

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