ironically i was looking for a good computer program to write, but before i wrote it i figured out the answer in my head... okay look,, the least possible difference is always going to be 14. period.. but here's why :) the possible number combinations are as follows: 24 42 62 82
26 46 64 84
28 48 68 86 you don't need to do write them down or figure them out in order to figure out the least possible combo... all you have to do is re-read what the question is asking....
"http://wiki.answers.com/Q/Find_the_least_possible_difference_of_two_2-digit_numbers_that_use_the_digits_2_4_6_and_8_only_once_in_each_number" you don't need to do anything except find the two numbers whos values are closest together and when subtracted produce the least ammount; which in your case, would be the median numbers. the combos above should help you see this, but the combination of 62 and 48 use all the digits and produce the lowest number. 62-48=14 any other combos of numbers produce higher results make sure that you do not use the same number twice or else you will not come up with the right answer. fun question!!
10 + 23 = 33 Lowest possible real number 97 + 86 = 183 Highest possible real number 02 + 13 = 15 Lowest possible number 97 + 86 = 183 Highest possible number
The answer is 39. 3+9=12, 3x9=27. 12+27=39.
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
6*5*4*3*2*1=720 possible numbers
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
to do it the long way do it by long division to do it the short way put it in the calculator 2 digits numbers are just the numbers between10-99 and one digits numbers are just the numbers between 0-9.
36
10 + 23 = 33 Lowest possible real number 97 + 86 = 183 Highest possible real number 02 + 13 = 15 Lowest possible number 97 + 86 = 183 Highest possible number
The answer is 39. 3+9=12, 3x9=27. 12+27=39.
We're talking about 3-digit numbers that you can make out of 3, 5, 7, and 9.-- The biggest one possible is 975.-- The smallest one possible is 357.-- Their difference is 618 .
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
9x8x7x6x5x4x3x2x1 or 9! which equals 362880 possible combinations if no digits are repeated
This cannot be answered. This will have to be written to where it can be understood.
6*5*4*3*2*1=720 possible numbers
Assuming that the first digit can't be zero: If repetition of digits is permitted: (5 x 6 x 6) = 180 numbers of 3 digits. If repetition of digits is not permitted: (5 x 5 x 4) = 100 numbers of 3 digits.
28
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.