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0.1 N iodide would be 0.1 moles of the iodide salt (e.g. KI) per liter of solution. For 500 ml, you would need 0.05 moles of the iodide salt. You need to state the salt (KI, NaI, LiI, etc.) in order to determine the actual mass required.
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How much of lead nitrate will be required to prepare 500ppm solution?
In order to prepare 500 ppm of lead solution from lead nitrate dissolve 0.799 gm of lead nitrate in 1000ml of water--add 1 or 2 drops of nitric acid.
How many mL of a 20 percent solution are needed to prepare 500 mL of a 5 percent solution?
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
You need to prepare a 4M concentrated solution for a lab and only need 500 mL of total solution. If you use enough water to bring the volume to 500 mL how many grams of sodium chloride would you need?
You need 116,88 g dried and pure sodium chloride.
How many grams of sodium chloride are required to prepare 500.0 mL of a 100 M solution?
In this instance, 50 mol of sodium chloride is needed and molar mass of NaCl is 58.5 g/mol. Hence the mass we need is 29250 g. But this amount of salt could not be dissolved in 500 ml of water, so we cannot prepare this solution practically.
Which of the following will result in a medicine dissolving fastest in 500 mL of water?
A water solution of this medicine is obtained.
How do you dilute 500 gallons of 31 percent to 15 percent?
To dilute 500 gallons of a 31% solution to a 15% solution you would add 533.33 gallons of the dilutant. For example, if you have 500 gallons of a 31% saline solution you would add 533.33 gallons of water to create 1033.33 gallons of a 15% saline solution.
What is the dilution of 1000 ppm to 500 ppm?
5ml of the 1000 ppm solution in 95ml distilled water gives a 500ppm solution
How do you prepare 500 mils 1 potassium hydroxide from N potassium hydroxide solution?
A mil is a measurement that equals one-thousandth of an inch, or 0.001 inch.
How do you prepare 0.5N KOH solution?
What is the Process for standardization of 0.5NKOH using Sodium Hydrogen phthalate.
Suppose you prepare 500 mL of a 0.10 M solution of some salt and then spill some of it What happens to the concencentration of the solution left in the container?
If the spill occurs after solution of the salt is complete, the concentration of the solution left in the container remains unchanged, because by definition of solution, the amounts of solvent and solute spilled will have the same proportions as in the original solution.
How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
What is the concentration of the hydroxide ion in a solution if 0.12 mol of strontium hydroxide are dissolved in water and the final solution volume is 500 mL?
.48 = [OH-]
