 |
How can a network with 6 segments still comply to the 5-4-3 rule? |
[Edit] |
Answer
It's been awhile, but here goes:
The 5-4-3 rule is part of the 802.3 spec for Ethernet networks. Origianally written to define timing for end to end signal propagation in a 10Base-5 nework. A station transmitting at one end of the network must be able to detect a collison that occured at the far end of the network before it's timer allows it to transmitt again. The spec says 5 segments of 500 meters sepatated by 4 repeaters (worst case). Under these conditions, adding a 6th segmant would put the network out of spec. If the 5 segments were 50 meters, theoretically the network would functional, but be out of compliance with 802.3's 5-4-3.
A more modern day example would be a 10Base-t or 100Base-T network with a backbone hub (Hub1) and 5 uplinked hubs (Hub2-Hub6)
Although there are 6 segmants, Station1 (connected to Hub2) and Station2 (connected to Hub6) communication would be in 5-4-3 compliance because it only crosses 3 segments and 3 repeaters. (Hub2--Hub1--Hub6)
I know it's quick an dirty, but I hope it helps ...BruceB
First answer by Bruceb. Last edit by Bruceb. Contributor trust: 22 [recommend contributor]. Question popularity: 51 [recommend question]
Answers.com > Wiki Answers > Categories > Technology > Computers > Computer Networking > How can a network with 6 segments still comply to the 5-4-3 rule?
Our contributors said this page should be displayed for the questions below. (Where do these come from ) |
| If any of these are not a genuine rephrasing of the question, please help out and edit these alternates. |
