Since glacial acetic acid is 17.4N, you just use (M1)(V1) = (M2)(V2).Example: If you want to prepare 100mL of 6N: (17.4N)(x mL) = (6N)(100 mL). So, you need 34.5 mL of glacial, dilute to 100 mL with...
Molecular Weight of Acetic acid=60.05density: 1.049 gr/cm30.5 molar=60.05/2= 30.025 gryou have molecular weight and density of Acetic acid so you can find the volume:d=m/v => v=30.025/1.049= 28.62...
Weigh 60 grams of Glacial Acetic acid into a 1 liter volumetric flask. Make up to the 1 liter mark with distilled water. There is now a 6% (w/v) solution.