The Gibbs free energy change is calculated from the expression Δ G = Δ H - T(Δ S) For the combustion of ethene (assuming it takes place at 25oC): C2H4 + 3O2 --> 2CO2 + 2H2O you need to find the enthalpy and entropy changes, which are Δ H (combustion) = - 1400 kJ/mol Δ S (combustion) = - 1102 J/mol/K Substituting into the first equation, remembering to divide the entropy value by 1000 because it's in J per mol per kelvin, not kJ, and converting the 25 degrees C to kelvin, we get: Δ G = -1314.35 kJ http://www.docbrown.info/page07/delta3SGc.htm
2C2H6 + 7O2 ----> 4CO2 + 6H2O
C - C ----> 347 * 2 = 694
C - H ----> 435 * 12 = 5220
O - O ----> 497 * 7 = 3479
total = 9393 KJ/Mol
C- O -----> 803 * 8 = 646
H -O ----> 464 * 12= 5568
total = 11992 enthlphy change =
9393 - 11992
=-2599 KJ/mol
ΔG°rxn = (2 mol)(-394.4 kJ/mol) + (2 mol)(-228.6 kJ/mol) - (1 mol)(68.15 kJ/mol) - (3 mol)(0 kJ/mol)
-51.88 kJ/g
ethane + Oxygen --> Carbon dioxide + Water
Ethane has no structural isomers and hence there is no n-ethane and iso-ethane.
Ethane is an allotrop of carbon.
That would be combustion with the products being carbon dioxide and water (assuming complete combustion) and a release of energy.
-51.88 kJ/g
i at first wrote out the enthalpies of combustion for hydrogen ethene and ethane and then manipulated the equations , ultimately my answer ended up being -137 but when i tried to find out the enthalpy on google it just came up this quiestion did you find out what the answer was!?
Yes. Ethane can undergo combustion, in which it reacts with oxygen to produce carbon dioxide and water. 2C2H6 + 7O2 --> 4CO2 + 6H2O
Yes. Ethane can undergo combustion, in which it reacts with oxygen to produce carbon dioxide and water. 2C2H6 + 7O2 --> 4CO2 + 6H2O
Combustion.
Ethane does not have any molecule of carbon dioxide. However when ethane undergoes combustion then two molecules of carbon dioxide are formed (as ethane contains two carbon atoms).
Yes there are. These gases are hydrogen,methane,ethane,propane,butane,pentane. Hope this helped! ;)
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Combustion of Ethane: 2C2H6+7O2-->4CO2+6H2O Combustion of Ethanol: C2H5OH+3O2-->2CO2+3H2O
H. T. Lai has written: 'Numerical study of contaminant effects on combusstion if hydrogen,ethaneand methane in air' -- subject(s): Hydrogen fuels, Carbon dioxide, Nitrous oxides, Water, Ethane, Rection kinetics, Contaminants, Methane, Combustion chemistry 'Numerical study of contaminant effects on combustion of hydrogen, ethane and methane in air'
ethane + Oxygen --> Carbon dioxide + Water
Not exactly. Natural gas is mostly methane with small amounts of ethane and thiols. Incomplete combustion of this will yield some carbon monoxide.