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Molar mass of KOH = 39.1+16.0+1.0 = 56.1
Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
Wiki User
∙ 10y ago
Wiki User
∙ 11y ago1 mole KOH = 56.105g KOH
234.1g KOH x 1mol KOH/56.105g KOH = 4.171 moles KOH
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How many grams of solid KOH is necessary to prepare 220.0 ml of 0.500 M KOH solution?
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
What is the molarity of a solution with 0.2 moles of KOH in 100 mL of water?
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
What mass of KOH is needed to make 400mL of 725 M KOH?
I assume you mean 7.25 M KOH, but the process is the same anyway.Molarity = moles of solute/Liters of solution ( 400 ml = 0.4 Liters )7.25 M KOH = X moles KOH/0.4 Liters= 2.9 moles KOH (56.108 grams/1 mole KOH)= 163 grams potassium hydroxide needed===============================
How many moles are present in 34 grams of KOH?
Depending upon how precise your masses are, KOH has a molar mass of about 56, so your answer is about 34/56.
What mass of h2o is produced when 0.400 moles of koh react completely in the following equation koh plus hcl equals kcl plus h2o?
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
How many grams of solid KOH is necessary to prepare 220.0 ml of 0.500 M KOH solution?
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
What is the molarity of a solution with 0.2 moles of KOH in 100 mL of water?
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
What mass of KOH is needed to make 400mL of 725 M KOH?
I assume you mean 7.25 M KOH, but the process is the same anyway.Molarity = moles of solute/Liters of solution ( 400 ml = 0.4 Liters )7.25 M KOH = X moles KOH/0.4 Liters= 2.9 moles KOH (56.108 grams/1 mole KOH)= 163 grams potassium hydroxide needed===============================
How many moles are present in 34 grams of KOH?
Depending upon how precise your masses are, KOH has a molar mass of about 56, so your answer is about 34/56.
How many grams of solid KOH is necessary to prepare 60ml of 2M KOH solution?
Moles KOH = Molarity x Volume = 0.214 moles/liter x 0.0602 liters = 0.0129 moles KOH. Remember, 60.2 mL = 0.062L
What mass of h2o is produced when 0.400 moles of koh react completely in the following equation koh plus hcl equals kcl plus h2o?
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
How many moles of KOH are represented by 1.350g of KOH?
1 mole of KOH is 56.1074 grams1.350 g/56.1074 g =0.02406 (2.406 x 10^-2) moles of KOH
How many grams of oxygen are formed when 6.21 moles of KOH are formed 4KO plus 2H2O equals 4KOH plus O2?
49.7g O2
How many moles of potassium hydroxide are required to prepare 300 mL of 0.250 M solution?
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
Which equation shows how to calculate how many grams(g) of Mg(OH)2 would be produced from 4 mol KOH. The balanced reaction is mgcl2 plus 2koh mg(oh)2 plus 2kcl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Which equation shows how to calculate how many grams (g) of Mg(OH)2 would be produced from 4 mol of KOH The balanced reaction is MGCl2 plus 2KOH Mg(OH)2 plus 2KCl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
What will be the molarity for a solution prepared by dissolving 50 grams of KOH in 700ml of water?
Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY
