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This is to be calculated from at least two identical kinetic experiments1) only varying the temperature. Use the Arrhenius equation2):

kT = A * e^[-Ea/R.T ]in which: (all in SI units: J, mole, K as applicable)
  • kT = rate constant, measured at temp. T1 or T2
  • A = Arrhenius factor, (largely) independent of temperature (if |T1-T2| < 25 K)
  • e^ = power of e, e being the base of the natural logarithm, e=2.71828...
  • Ea = activation energy of the particular reaction (independent of temperature and concentration)
  • R = universal gas constant
  • T = temperature (T1 or T2, both > 250 K)

1) All reaction parameters should be the same except temperature.

2)The Arrhenius equation is a simple, but remarkably accurate, formula for the temperature dependence of the rate constant, and therefore, rate of a chemical reaction.

The equation was first proposed by the Dutch chemist J. H. van 't Hoff (who was my 'chemical grandfather' when I was 14, at my first chemical college) in 1884; five years later in 1889, the Swedish chemist Svante Arrhenius provided a physical justification and interpretation for it.

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Q: How do you calculate energy of activation in catalysis?
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