In exactly the same way as you do so for a single-phase load. It's the product of the power of the load, expressed in kilowatts, and the during of operation, expressed in hours. (And the symbol of kilowatt hours is 'kW.h', not 'kwh')
The formula for single phase from a three phase system is Kilowatts = I x E x pf/1000. For a three phase system it would be Kilowatts = I x E x 1.73 x pf/1000.
There is software that can be downloaded to help calculate the number of turns for a three phase motor. There are also diagrams which can be found for the most frequently used calculations.
A 7.5 kW three phase load will be balanced by the manufacturer. When connected to a three phase source the line current on each phase will be equal.
Single phase power from a L-L voltage of 208 volts is calc'd: P = V(phase to phase) * I (individual phase current) / sqrt(3) Total power from all three legs is the above P * 3. P is in watts; continuous sampling will result in watt hour measurements; 1000 x this is kWh's.
If you have three adjacent houses each with a single-phase supply taken from different phases in a three-phase cable in the street, the total power is equal to the sum of the powers in each of the three phases.
output power/Rated power
To calculate kWh a time component is needed for the hours.
No. For three phase, you need a minimum of a two element meter.
You can't. Measure the amperes simply tells you what the current is.
Measuring the current in each phase (or do you mean 'line'?) will not give you sufficient information to work out what you are asking for.
It depends on the voltage. Please restate the question and provide the voltage. In general, however, simply divide total power by KV to get KA. Remember the KWH is an integral, so you need to back calculate KW. If the month is a 30 day month, then KW is KWH / 30 / 1440. Then, if the load is star, simply divide by three; if the load is delta, divide by three and multiply by 1.732, the square root of 3. Example: 480 three phase running star. 8000 / 30 / 1440 is 185 amperes. 185 divided by 3 is 62 amperes per phase. For delta, that becomes 107 amperes.
By knowing the voltage you could use calculate the wattage. Power equals volts times amps. Divide by 1000 to get kilowatts.
If, Ct value = 50 meter unit = 30 so, 50 x 30 = 1500 kwh
There is software that can be downloaded to help calculate the number of turns for a three phase motor. There are also diagrams which can be found for the most frequently used calculations.
You are, presumably, talking about an unbalanced three-phase load. The answer is no, because the wattmeter takes unbalanced loads into account.
You will need to determine the power per phase, and add them up to give the total power of the three-phase load. To do this, you will need to multiply the phase-voltage by the phase current by the power factor -for each phase.
The formula you are looking for is - phase voltage/1.73 = phase to neutral voltage.
For a balanced load, you don't have to worry about phase values when you want to determine the power (or, in this case, the energy), whether delta or wye. Rather, you always use line values:P = 1.732 VL IL cos (phase angle)For an unbalanced load, however, you need to measure the phase voltage and phase current and power factor for each of the three phases, and add them together:P = [VpIp cos (phase angle)]phase A +[VpIpcos (phase angle)]phase B+[VpIp cos (phase angle)]phase CTo then calculate the energy expended in kilowatt hours, you need to multiply the total power (as calculated above), expressed in kilowatts, by the time for which the load is operating, expressed in hours.