The maximum power output of the transformer is measured in VA or KVA, (volt-amps) or thousand (volt-amps). That will will marked or stamped on the transformer. If you want to measure the amount of power being used by the Xformer, measure the Line side current in amps with an amprobe and multiply by the line voltage to it. The result in watts is the power consumption.
It is a variable autotransformer, a transformer with a sliding contact on the winding connected to a control knob, that allows the output voltage to be varied.
A delta connected appliance can be connected to a 3-phase system by leaving the neutral unconnected. The appliance must be properly earthed.
why three phase induction motor is delta connected
Balanced Star (Wye) Connected Systems:Line Voltage = 1.732 x Phase VoltageLine Current = Phase CurrentBalanced Delta Connected Systems:Line Voltage = Phase VoltageLine Current = 1.732 x Phase Current
With three windings, you have six terminals. Call them A1, A2, B1, B2, C1, and C2, representing phase A, B, and C. In the delta configuration, A1 is connected to C2, C1 is connected to B2, and B1 is connected to A2. Power is from phase to phase - A1C2, C1B2, and B1A2. In the wye configuration, A2, B2, and C2 are connected together, and are usually connected to neutral. Power is from phase to neutral - A1, B1, and C1.
circuit characteristics.
An autotransformer is a transformer with at least two windings where a part of one winding (the common winding) is shared between both primary and secondary outputs.
basicaly the two inductors work as an autotransformer,providing a phase shift of 180 degree
There is no neutral in a delta connection, because that is the definition of delta, a power configuration where current flows from phase hot to phase hot. The loads are A-B, B-C, and C-A. Contrast this with star, where there is a neutral, and the loads are A-N, B-N, and C-N.
The voltage of a winding that is connected in star is 1 over the square root of three, 1 / 1.732, or 0.5774, of the voltage if that winding were connected in delta. This results in a star power of 1/3, or 0.3333, of the delta power.Similarly, if you know the winding current in delta, you can calculate the star current by multiplying by 1.732.This all presumes that the neutral point of the star is symmetrically centered in the middle of the phase triangle.
yes
High or "wild" leg phase to ground.