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To solve boiling point elevation problems, you need to know the following things:
-- the identity of the solute (the thing you are adding to the liquid)
-- the identity of the solvent (the liquid)
-- whether the solute is molecular or ionic, and if ionic, how many ions it forms
-- the amount of solute (in grams or moles)
-- the amount of solvent (in kilograms)
-- the value of Kf of the solvent (for water, it is 0.52 K·kg/mol (or 0.52 °C molal-1)
Then you use the following equation:
∆T = i * Kf * m
where ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution.
The Kf of water for a boiling point elevation is known and is equal to 0.52 °C·kg/mol (or 0.52 °C molal-1). Notice it is positive -- for freezing point depression problems, the value of Kf is negative.
The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).
To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). If you are given the number of grams of solute, the number of moles is found from the mass and the molar mass of the solute.
grams of solute ÷ molar mass of solute = moles of solute
To find the molality, just divide the moles of solute by the kilograms of solvent moles of solute ÷ kilograms solvent = molality Note: If you are given the volume of the solvent instead of the mass, use the density of the solvent to convert -- the density of water is 1 kilogram per liter)
Liters of solvent * density of solvent = kilograms of solvent
Now just plug all the numbers into the equation at the top of the answer!
See the Web Links and Related Questions for more information!
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What quantity represents the ration of the number of moles of solute per kilogram of solvent?
Mol is a cocentration unit !
When a certain amount of calcium chloride (CaCl2) was dissolved 100.g of water the boiling point rose from 100.0C to 104.4C calculate the molality of this solution.?
Delta T = imKI = van't Hoff factor = 3 for CaCl2 m = molality = moles solute/kg solvent = ? K = boiling point constant for water = 0.512 Delta T = change in temperature = 4.4 deg C Plug in the values and solve for m
What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
What are the molality and mole fraction of solute in a 25.5 percent by mass aqueous solution of formic acid (HCOOH)?
The molality is 5,54.
Formula for molality?
== Molality== (1000xMolarity)/((1000xdensity of solution)- (MolarityxMolecular weight of Solute)) ==
What quantity represents the ration of the number of moles of solute per kilogram of solvent?
Mol is a cocentration unit !
What is the molality of a substance?
Molality is the number of moles of a solute divided by the weight of the solvent in kilograms.
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
The molality is 0,07.
What is molality?
Concentration
How are concentrations in solutions quantified?
through molarity,molality, normality. through molarity,molality, normality.
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality is 0,2.
Why you use molality in biology experiments?
Molality is used when temperature varies in an exothermic or endothermic reaction because it is not dependent on temperature or pressure. Molality does not depend on tempratute whereas molarity does.
When a certain amount of calcium chloride (CaCl2) was dissolved 100.g of water the boiling point rose from 100.0C to 104.4C calculate the molality of this solution.?
Delta T = imKI = van't Hoff factor = 3 for CaCl2 m = molality = moles solute/kg solvent = ? K = boiling point constant for water = 0.512 Delta T = change in temperature = 4.4 deg C Plug in the values and solve for m
What is the molality solution that has 3 mol of glucose in 6 kg if water?
This molality is 90,08 g/kg.
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of ethanol will be 5,91.
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
