Power (watts) = volts x amps
A volt-amp is a watt. (A volt times an amp is a watt.)
I=(KVA*1000)/(1.732*V) (Three Phase)
AMP=KW/1000*V*PF
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KW or KVA can be converted to one another but you cannot convert them to amps. You can compute amps by using this formula,
KW = I x V x 1.732 x P.F/1000 (Three phase)
KVA = I x V x 1.732/1000 (Three phase)
If you have KVA and voltage, simply divide KVA by voltage, after normalizing voltage to KV, and you get A. You don't need KW or power factor in this case.
Divide the watts by the voltage to get current (amps). 60W / 250V = about 1/4 Amp.
V=R*I and W=V*I so W=R*I*I Ex: 10V = 2R *5A 10V *5A= 50W 2R * 5A*5A=50W
The Ampere is the unit of electric current. It depends upon a voltage in order for it to occur, and the Volt is that unit. The Ohm is the unit of resistance and represents the difficulty of moving the electrons by the voltage.
copper loss is directly propostional to I (AMPERE) and iron loss directly propostional to V (VOLTAGE) then total losses is equal to volt ampere hence the rating of transformer in KVA. SULTAN
The rule of thumb for fusing the motor is 300% of the full load amps. To answer this question a voltage value for the motor is needed. That would depend on the type of electricity used and the type of motor. The answer will be different for DC, single phase AC, two phase AC, and three phase. There are many types of motors as well: split-phase, brush less, squirrel cage, synchronous, etc. Each one has different characteristics.
Voltage = Current * Resistance (Ohm's law)
Divide the watts by the voltage to get current (amps). 60W / 250V = about 1/4 Amp.
the formula for electric current is VI ,where v is voltage then I is the current. the unit used for current is ampere and volts for voltage. multiply the total I to the Voltage The formular of electric current is given by I=V/R ,I=P/V
Full load current can be calculated by the formula given below: P=SQUARE ROOT OF 3*V*I*POWER FACTOR P=1.732*V*I*PF suppose 3 kw motor three phase voltage assuming .85 power factor and 415 volt full load current will be 3*1000=1.732*415*I*.85 I=4.9 ampere(full load ampere)
amplification factor
V=R*I and W=V*I so W=R*I*I Ex: 10V = 2R *5A 10V *5A= 50W 2R * 5A*5A=50W
the formula for electric current is VI ,where v is voltage then I is the current. the unit used for current is ampere and volts for voltage. multiply the total I to the Voltage The formular of electric current is given by I=V/R ,I=P/V
The Ampere is the unit of electric current. It depends upon a voltage in order for it to occur, and the Volt is that unit. The Ohm is the unit of resistance and represents the difficulty of moving the electrons by the voltage.
Amps = Watts / (Volts x Power Factor). The Power Factor is one for resistive loads and decreases for inductive loads like motors.
copper loss is directly propostional to I (AMPERE) and iron loss directly propostional to V (VOLTAGE) then total losses is equal to volt ampere hence the rating of transformer in KVA. SULTAN
A motor's output is measured in watts because it has to supply energy to a mechanical load. The rate at which energy is supplied to a mechancial load is expressed in watts (it wouldn't make sense to express it in electrical units!). A transformer's output is expressed in volt amperes, because this is the product of the transformer's rated output voltage and its rated secondary current -the product of voltage and current in a.c. systems is the volt ampere. In order to express its output in watts, you would need to know the power factor of the load which it supplies (power equals voltage times current times power factor), and the manufacturer has no means of knowing this.
Depends on the voltage output, in a 12 Volt system 12.5 Amps equals 150 Watts, the equation is, (Amps x Volts)= Watts <<>> 12.5 amps is zero watts. Watts is the product of amps x volts. Without the voltage value an answer can not be given.