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How do you factor 125 -x cubed?

In: Math and Arithmetic, Algebra [Edit categories]

Answer:

Difference of two cubes: a³ - b³ = (a-b)(a²+ab+b²)

125 - x³
=

5³ - x^{3

=}(5 - x)(5² + 5x + x²)

=
(5 - x)(25 + 5x + x²)

First answer by Stevedene. Last edit by Stevedene. Contributor trust: 2 [recommend contributor ]. Question popularity: 1 [recommend question].

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How do you factor x cubed plus 125?
(x + 5)(x2 - 5x + 25)
How do you factor x cubed minus x?
X squared plus 1 and x minus 1 ---- Actually it is the following: x3-x x(x2-1) x(x+1)(x-1)
How do you factor x cubed - 25x?
x3 - 25x = x (x2 - 25) = x (x + 5) (x - 5)
How do you factor x cubed?
x times x times x equals x cubed
How do you factor x cubed minus 36 x?
x^3 - 36x Factoring out x from both the terms we get = x(x^2-36) Using the relationship, a^2 - b^2 = (a-b)(a+b) we get = x(x-6)(x+6)