How do you find equidistant points on a globe?

Construct perpendicular bisectors for 2 of the segments formed from 3 points. Note: this will be the center of the circle that has all three points on it's circumference.

Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.

-- Draw a line segment from one point to the other. -- Construct the perpendicular bisector of the line segment.. -- Every point on the perpendicular bisector of the line segment is equidistant from...

shape of a pyramid

For three points, (x1,y1), (x2,y2) & (x3,y3), you can set up 3 distance equations with variables x, y & z: z^2 = (x-x1)^2 + (y-y1)^2 z^2 = (x-x2)^2 + (y-y2)^2 z^2 = (x-x3)^2 + (y-y3)^2 3...