The volume of the shed is width times length times height. So height is 440/(10x8) = 44/8 = 11/2 = 5 1/2. However, this is the average height. The shed could be 6 feet high at one end and 5 feet high at the other. It could also be 11 feet high at one end and 0 feet high at the other. So the maximum interior height is 11 feet.
28 plausibly. There are an infinite number of possibilities. If we assume all angles are equal, it narrows the field. * * * * * Wrong answer. The interior angles of a 30 sided polygon sum to (30 - 2)*180 = 5040 degrees. And you do not need to assume that the angles are equal. They can even be reflex angles.
On the basis that you are familiar with terms such as "tetrakaidecagon" I assume you are mathematically at a stage where angles are measured in radians and not degrees. Then the interior angles of a 14 sided polygon sum to (14-2)*pi radians or 12*pi radians.
Assume you are referring to polygons with interior angle measuring less than 90°There are few shapes that have that measurement. They are:isosceles triangle with no obtuse and right anglesequilateral triangle
In euclidean (plane) geometry, the sum of the interior angles of any triangle is 180 degrees. Add the two angles you know (right angles = 90 degrees) and subtract that sum from 180. Without more information on the problem, that's the most I can assume
An interior angle in a 13-gon can have any measure between 0 and 360 degrees (excluding the two end values), subject to the constraint that the sum of these angles is (13-2)*180 = 1980 degrees. If (and only if) the 13-gon is regular - and there is no reason to assume that it is - each angle will be 1980/13 = 152.3 degrees.
I assume the question refers to the sum of the interior angles even though angles are not mentioned anywhere in the question. The sum is 360 degrees.
It is not. The sum of all the interior angles is related to the number of sides but, unless the polygon is regular, each interior angles can have any value in the range (0, 360) degrees - the traingle being an exception where the maximum angle must be less than 180 degrees. There is nothing in the question that suggests that the polygon is regular and since only a minority of polygons are regular, you may not assume that it is a regular polygon.
I assume it is the space (in 3 dimensions) that something occupies
By measure, I will assume you mean what is each interior angle, or what is the sum of the interior angles. The sum is 8,640 degrees, and each interior angle is 172.8 degrees. Side fact: that means there is an exterior angle of only 7.2 degrees. A polygon with 1000 sides would have an exteror angle of only 0.46 degrees. However, and this makes sense, no matter how many sides in the polygon, the interios angle will not add up to 180.
Sum of interior angles of a nonagon = (n-2)*180 = 7*180 = 1260 degrees. That is as far as you can go with the information given. If, and there is no reason to assume so, the nonagon is regular then the internal angles are the same and each is 1260*9 = 140 degrees.
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. So, the sum of the interior angles of an 18-gon is 16*180 = 2880 degrees. Subject to this sum, each particular angle can range from 0 to 360 (not inclusive) degrees. If you assume that all the angles of the 18-gon are equal, then you can say that each angle is 2880/18 = 160 degrees. However, there is absolutely no reason to support such an assumption.
28 plausibly. There are an infinite number of possibilities. If we assume all angles are equal, it narrows the field. * * * * * Wrong answer. The interior angles of a 30 sided polygon sum to (30 - 2)*180 = 5040 degrees. And you do not need to assume that the angles are equal. They can even be reflex angles.
On the basis that you are familiar with terms such as "tetrakaidecagon" I assume you are mathematically at a stage where angles are measured in radians and not degrees. Then the interior angles of a 14 sided polygon sum to (14-2)*pi radians or 12*pi radians.
Sum of interior angles = (n-2)*180 degrees = 1080 deg So (n-2) = 1080/180 = 6 => n = 8. The polygon is, therefore, an octagon. However, there is no reason to assume that the interior angles of this polygon are all the same - they could all be different with the only constraint being their sum. IF, and that is a big if, the polygon were regular, then all its angles would be equal and each interior angle = 1080/8 = 135 degrees.
Assume you are referring to polygons with interior angle measuring less than 90°There are few shapes that have that measurement. They are:isosceles triangle with no obtuse and right anglesequilateral triangle
I would assume Russia
In euclidean (plane) geometry, the sum of the interior angles of any triangle is 180 degrees. Add the two angles you know (right angles = 90 degrees) and subtract that sum from 180. Without more information on the problem, that's the most I can assume