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How do you find the vertex of the parabola associated with a quadratic equation?

In: Math and Arithmetic, Algebra, Geometry [Edit categories]

Answer:

You must first solve the equation for x, find the midpoint between the two x coordinates and substitute it into the equation to find the y coordinate

I.E.

If your equation was y=x^2+4x-5

1. Factorise the Equation and solve for x. x^2+4x-5 = (x+5)(x-1)

So x+5=0

x = 0 - 5

x=-5

And x-1=0

x = 0 + 1

x = 1

So x = -5,1

Find the mid point/average: (-5+1)/2 = -2

So the x coordinate of the vertex is -2.

Substitute this into the equation x^2+4x-5: (-2)^2 + 4*(-2) - 5 = 4 - 8 - 5 = -9

So the Coordinate of the vertex is (-2,-9).

Hope this Helps, message me if you want more info.

First answer by Aeroplane380. Last edit by Aeroplane380. Contributor trust: 2 [recommend contributor ]. Question popularity: 1 [recommend question].

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