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cubic units
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∙ 13y ago
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HOW TO CALCULATE SQFT?
Multiply the length measurement by the width measurement and this will give you the area in SQFT if your measurements of length and width were made in feet.
Can you figure height of a 3 d object if you only have depth and width?
No If you have a picture of it you can use the measurements you know to give you the scale of the picture. Or if you don't have a picture you can use the length of your thumb viewed at arms length, and then calibrate using a known object, or better still, the known width.
What is the length width and height of 3D object called?
The object's dimensions. Multiplied together they give the objects volume.
How do you find volume if you only know height?
You cannot, to find an unknown, you need at least two knows facts. IE if the length and width give you area, you cannot get the area without BOTH the length and width.
Give an example of volume?
Volume is length times width times height. ^_^ Say, a 3-D rectangle. height: 8cm length: 5cm width: 4cm 5x4x8 5x4=20 20x8=160 And remember, volume is always cubed. Volume of the rectangle = 160cm3
How do you solve for height if you have volume length and width?
The formula for volume is length x width x height = volume. So if you take the volume and divide it by the length and width it should give you the height.
HOW TO CALCULATE SQFT?
Multiply the length measurement by the width measurement and this will give you the area in SQFT if your measurements of length and width were made in feet.
How do you calculate density with length and width height?
Length, width and height will give you volume. You still cannot compute the density unless you know the mass.
How do you calculate density with only length width and height?
Length, width and height will give you volume. You still cannot compute the density unless you know the mass.
How do you solve the volume of a pyramid?
# Square Pyramid:#* Identify the length and width of the base. Write your measurements down. #* Calculate the area of the base. This is done by multiplying the width by the height. Write the answer down. #* Multiply the area of the base by the height. Write this answer down, too. #* Multiply the previous answer by one third, or divide by 3. This will give you the final answer. # Triangular Pyramid:#* Identify the length and width of the base. Write the measurements down. #* Calculate the area of the base.Multiply the length by the width, then multiply by one half (or divide by 2). This is the area. Write the answer down. #* Multiply the area of the base by the height of the pyramid.#* Multiply your answer by one third, or divide by 3. This will give you the volume.Source: WikiHow
How do you find the area of a box?
length x width x height will give the VOLUME. Length x width gives the AREA. Which do you want?
Can you figure height of a 3 d object if you only have depth and width?
No If you have a picture of it you can use the measurements you know to give you the scale of the picture. Or if you don't have a picture you can use the length of your thumb viewed at arms length, and then calibrate using a known object, or better still, the known width.
Give the formula in the volume of rectangular prism?
It is Length * Width * Height in the appropriate cubic units.
To find the mass of a rectangular object you multiply the object's length width and height. True or false?
False on two counts. A rectangular shape is 2-dimensional and so can have no mass. If it is rectangular but has length, width and height then it is a cuboid object. Then, multiplying the length width and height will give the volume, not the mass.
How many cbms per 53' container?
You need to give the width and height of the container as well as the length
What is the volume of a book that has the width of 5cm height of 20cm and a length of 10cm?
Volume is determined by multiplying the height by the width and then the depth. This would give you 2100 cubic centimeters.
What is the length width and height of 3D object called?
The object's dimensions. Multiplied together they give the objects volume.
