How do prepare 0.1n potassium hydroxide?

Answer 1

74.5513 g/mol KCl * * 1 mol/eq * 0.1 eq/L = 7.455 g/L

So accurately weight 7.455 g dry, analytical grade KCl and dissolve in volumetric flask of exact 1.000 Liter and fill up with water to the 1L-mark, close and carefully mix by repeated inversion. In this way you can get an exact 0.1000 N KCl standard solution.

Answer 2

0.01M ammonium hydroxide (NH4OH) is a concentration of 0.01 moles NH3 in 1L of water (out of solution NH4OH does not exist, it is just ammonia: NH3).

NH3 has a molecular weight of 18 g/mole, so 0.01 moles is 0.18 g. Placing 0.35g of NH3 in 1L water will give a 0.01M solution of NH4OH.

Answer 3

I believe the problem is on the normality unit since the preparation of standard solution in unit of mol is a simple mathematics. Sodium hydroxide (NaOH) had OH as functional group and is only 1 per active molecules. The Normality of 0.02 N is then equal 0.02 mol/L.

Preparing 0.02 mol/L is best start at 1 mol/L standard solution by dissolve 40 g of NaOH pallets to 1 L of distilled water in volumetric flask (NaOH is 39.997 g/mol). Then pipette out 20 ml of 1mol/L solution into 1000 mL volumetric flask. Add up with distilled water until it reach the mark and you got yourself a 0.02 N sodium hydroxide solution.

Please handle NaOH with care.

Answer 4

4g NaOH in 1L = 0.1N NaOH

Answer 5

how to prepare 0.1 n koh solution

Answer 6

13ml in 1000

Answer 7

13.61 in 1000ml distilled water