0
To prepare a 1 M (molar) solution of hydrochloric acid (HCl), you would need to dilute concentrated HCl (typically 37% w/w) with water. Measure out the appropriate volume of concentrated HCl using a volumetric flask and then add water to reach the desired final volume, ensuring proper mixing. It is crucial to handle concentrated HCl with care, as it is a corrosive and hazardous substance.
Still curious? Ask our experts.
Chat with our AI personalities
Fran
Lao
MaxineTo prepare a 1 M (molar) solution of hydrochloric acid (HCl), you would need to add 36.5 grams of hydrochloric acid to enough water to make a final volume of 1 liter. This is based on the molar mass of HCl (36.5 g/mol). Make sure to add the acid to water slowly and with proper safety equipment due to the exothermic nature of the reaction.
Exactly how you prepare will depend on what you are starting with. Typically to make a 1 M HCl solution, you will be starting with a stock solution of more concentrated HCl that you will then dilute.
See the Related Questions for complete instructions on how to prepare a solution by diluting a stock solution.
1M HCl Solution*Concentrated HCl. its 37.5%.
*The density of concentrated HCl is 1.189g/ml we will need this number as well, and of course the Atomic Mass of HCl 36.46
* Calculation=((37.5/100)(1000)(1.189))/36.46 = 12.2M
*If HCl concentrated is 12.2 M then to make a 1L solution of 1M HCL
(12.2) x = 1(1)
x = 1(1)/(12.2)
x=0.082ml/ml of water
x = 82mL HCl per liter
0.1M IS THE CONCENTRATION THAT SHOULD BE PREPARED,i.e. C2.WE SHOULD HAVE THE IDEAL VOLUME IN WHICH WE WANT TO PREPARE THE SOLUTION,SAY 2L, IS OUR V2.IF WE ARE TAKING THE HCL FROM A 12M Hcl,C1,THEN WE SHUOLD FIND OUR V1. C1=12M V1=? C2=0.1M V2=2L C1V1=C2V2 12M.V1=0.1M.2L V1=0.2M.L/12M =0.016L =16.6ml ADD 16.6ml OF HCL IN A 2L VOLUMETRIC FLASK AND WITH SOME DISTILLED WATER.SWIRL TO MIX AND ADD DISTILLED WATER UP TO THE MARK OF THE VOLUMETRIC FLASK. MALAPANE L.A For safety purposes you should always add acid to water, especially in the case of an acid like sulfuric acid. When mixing acid and water you should add some of the water to your flask, then add the acid and swirl to mix, then add the balance of the water.
Suppose your question is to prepare 1 mM HCl of 100 ml using 1 M HCl?
Take equation V1N1 = V2N2
V1 is the volume of your 1mM HCl, here V1= 100 ml
N1 is the your desired concentration of HCl. here N1= 1 mM
V2 is the required volume (ml) of 1M HCl to prepare 100 ml of 1mM, here V2
N1 is the concentration of your available stock acid, here N1= 1M
1mM= 0.001 M
Now, V2 = (100ml x 0.001)/1 = 0.1 ml
Therefore, 0.1 ml of 1 M HCl with remaining 99.9 ml of distilled water addition will give 100 ml of 1mM HCl from 1M HCl stock.
To calculate this conncetration we have to use the formula of molarity: M = mol solute / L solution. Now, considering that a stock solution of Hydrochloric Acid (HCl) is calculated to be 12.178 M based on a density of 1.2 g/mL, a formula weight of 36.46 g/mol, and a concentration of 37% w/w.
Therefore, to make 1 L of a 0.1 M solution, we have to slowly add 8.212 mL of the HCl stock solution to 250 mL deionized water, and adjust the final volume of solution to 1000 mL with deionized water.
To prepare 0.1M HCl we should be given as
Density of HCl=1.19 g/ml approx.
Purity of HCl=37% w/w approx.
Molecular weight of HCl=36.5 approx.
Now (i)
Convert w/w into w/v of HCl
37% × density = 37/100×1.19= 0.4403 kg/L
Now(ii)
Convert w/v into mol/v
0.4403 kg/L / 36.5 g/mol ×1000= 12M (HCl)
Now(iii)
M1V1=M2V2
12×V1= 0.1 × 1000
V1= (0.1×1000)/12
V1=8.33 ml of HCl will be used to make up volume of water up to 1000 ml for 0.1M HCl.
Add your answer:
Earn +20 pts
Why you use 85 ml Conc HCl for 1 M HCl?
To prepare 1 M hydrochloric acid (HCl) solution, you usually need to dilute concentrated HCl solution (~35-37% HCl) with water in a specific ratio. The specific volume of concentrated HCl needed depends on its concentration and the final volume of the 1 M solution you want to make. In this case, 85 ml of concentrated HCl is likely to be the volume needed to make 1 L of 1 M HCl solution.
How do you prepare a 0.0001 M soulution HCL using 0.1 M of HCl?
you need to make 1000 times dilutions, this could be done in multi-steps: transfer 1 ml 0.1 M HCl into 100 ml volumetric flask and complete volume with water --------(1) from solution (1) transfer 2 ml into 20 ml volumetric falsk and complete volume with water, this is 0.0001 M HCL.
What volume of a 1.50 M HCl solution should you use to prepare 2.00 L of a 0.100 M HCl solution?
To prepare a 0.100 M HCl solution from a 1.50 M HCl solution, you need to use the dilution formula, which is M1V1 = M2V2. You would need to use (V_1 = \frac{M_2V_2}{M_1}) to calculate the volume needed. Plugging in the values, you would need to use ( V_1 = \frac{0.100 M \times 2.00 L}{1.50 M} = 0.133 L or 133 mL) of the 1.50 M HCl solution.
How to prepare HCL solution?
To prepare a hydrochloric acid (HCl) solution, you can dilute concentrated hydrochloric acid with water. Always add the acid to water slowly while stirring, never add water to acid, as it can cause splattering. Be sure to wear appropriate protective gear and work in a well-ventilated area when handling HCl.
How many mL of HCL do you measure to prepare a liter of 0.5N HCL?
To prepare a liter of 0.5N HCl solution, you would measure 50 mL of concentrated hydrochloric acid (37% HCl by mass) and dilute it to 1 liter with distilled water.
