How do you resolve ambiguity in multiple inheritance?

Answer 1

Use virtual base classes. It is best if the common base class has no member variables and all member methods are pure-virtual. The multiple-inheritance class must provide all the implementation for the pure-virtual methods, even if the direct bass classes also provide their own implementations.

Answer 2

It is not clear what "multiple inheritance" means but ambiguities in wills are resolved in court on an action to construe the will. There are two types of ambiguities. Ones that arise from ambiguous language in the will and ones that arise from facts outside the will. The court will take evidence of the facts relevant to the ambiguity to resolve it. The idea is to ascertain the decedent's probable intent when making the will in order to clarify the matter.

Hi,

In multiple inheritance the ambiguity arises when same method name is being used by two derived class and furthur derivation from these two base classes. This is called Diamond problem. In order to solve this issue virtual base class concept is being used where base class is virtual to derived ones. For example, u have one base class A, and two derived class B and C, Now one more derived class from B and C is D. In this situation 2 subobject of A will be created (one from B and another from C).In order to avoid such situations we use virtual base class.

class A
{

public:
A(int a)
{
cout<<"Base class A"<}

}

class B:public class A
{
public:
B(int b,int a):A(int a)
{
cout<<"Derived class B"<}

}
class C:public class A
{
public:
C(int c,int a):A(int a)
{
cout<<"Derived class C"<}

}

class D:public class C,public class B
{
public:
D(int d,int c,int b):C(int c,int a),B(int b,int a)
{

}

}

main()
{
D d(1,2,3);
}

Output:
Base class A : 3
Derived class C : 1

Base class A : 3
Derived class B: 2


This issue is being solved by making class A as virtual and then output will be

Base class A : 3
Derived class C : 1
Derived class B: 2

Answer 3

There is no such thing. Ambiguity occurs in multiple inheritance where two or more base classes share a common member name.

In the following example, two base classes share common public member name, GetData(). The derived class inherits both, but you cannot call derived::GetData() because the compiler cannot tell which method to actually call.

#include <iostream>

class base1

{

public:

base1(int data=0):m_data(data){}

int GetData()const{return(m_data);}

private:

int m_data;

};

class base2

{

public:

base2(int data=0):m_data(data){}

int GetData()const{return(m_data);}

private:

int m_data;

};

class derived : public base1, public base2

{

public:

derived(int data=0):base1(data),base2(data){}

};

int main()

{

derived d(5);

int x = d.GetData(); // Ambiguous!

return( 0 );

}

To remove the ambiguity, you must explicitly call d.base1::GetData() or d.base2::GetData().

Answer 4

When you derive classes, ambiguities can result if base and derived classes have members with the same names. Access to a base class member is ambiguous if you use a name or qualified name that does not refer to a unique function or object. The declaration of a member with an ambiguous name in a derived class is not an error. The ambiguity is only flagged as an error if you use the ambiguous member name.

For example, suppose that two classes named A and B both have a member named x, and a class named C inherits from both A and B. An attempt to access x from class C would be ambiguous. You can resolve ambiguity by qualifying a member with its class name using the scope resolution (::) operator.

class B1

{

public:

int i; int j;

void g(int) { }

};

class B2

{

public:

int j;

void g() { }

};

class D : public B1, public B2 {

public:

int i;

};

int main()

{

D dobj;

D *dptr = &dobj;

dptr->i = 5;

// dptr->j = 10;

dptr->B1::j = 10;

// dobj.g();

dobj.B2::g(); }

The statement dptr->j = 10 is ambiguous because the name j appears both in B1 and B2. The statement dobj.g() is ambiguous because the name g appears both in B1 and B2, even though B1::g(int) and B2::g() have different parameters.

The compiler checks for ambiguities at compile time. Because ambiguity checking occurs before access control or type checking, ambiguities may result even if only one of several members with the same name is accessible from the derived class.

Answer 5

Hybrid, or multiple, inheritance in C++ can be ambiguous. To resolve this, you can qualify the name with its class name. For example.

class a {

int z;

...

}

class b {

int z;

...

}

class c : public a, public b {

...

something = z; // ambiguous

something = a::z; // un-ambiguous

}

Answer 6

Ambiguity in hybrid, or multiple inheritance is when the same named method or attribute of two different classes is inherited by one class. Example: a is a member of b and c. If you create a d that inherits from both b and c, d will contain two different a's, one from b and one from c. Unless you use scope resolution syntax, a reference to a within the context of d will be ambiguous. This would be in the form, for instance, of b::a, and c::a, instead of just a.

Answer 7

In languages like C, there might be ambiguity because of same method names in more than one parent class.

This is the main reason why Java does not support direct multiple inheritance.

Answer 8

You dont because Java does not support direct Multiple Inheritance

Answer 9

No there is no ambiguity in single inheritance

Answer 10

c