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Answer:
The key formula for solving a dilution problem is M1V1=M2V2 (alternately, MAVA=M BVB)
where concentration is M (measured in Molars, a unite of concentration-->Molars=moles solute/Liters solution) and the volume of solution is V.
M1V1 represents the inital conditions (pre-dilution), and M2V2 denotes the final conditions (post-dilution).
Plug in the three values you know to find the fourth value, which you are solving for.
Ex.
750mLs of a 0.5 M NaC2H3O2 solution is diluted with 250mL of H2O. What is the new concentration of NaC2H3O2?
Answer:
(0.5M)x(.750L)=(MB)x(.750L+.250L)
0.375ML=(MB)x(1L)
MB=0.375M
where concentration is M (measured in Molars, a unite of concentration-->Molars=moles solute/Liters solution) and the volume of solution is V.
M1V1 represents the inital conditions (pre-dilution), and M2V2 denotes the final conditions (post-dilution).
Plug in the three values you know to find the fourth value, which you are solving for.
Ex.
750mLs of a 0.5 M NaC2H3O2 solution is diluted with 250mL of H2O. What is the new concentration of NaC2H3O2?
Answer:
(0.5M)x(.750L)=(MB)x(.750L+.250L)
0.375ML=(MB)x(1L)
MB
First answer by GenDen92.
Last edit by GenDen92.
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