According to the documentation on MSDN, the following code should create an uncompressed volume texture DDS file that's 32x32x32 in size. Re-scale as you see fit. Note: a 128x128x128 RGBA texture will take up 8 MB of VRAM! #include <stdio.h> #include <stdlib.h> #include <math.h> #include <string.h> #define DDSD_CAPS 0x00000001 #define DDSD_HEIGHT 0x00000002 #define DDSD_WIDTH 0x00000004 #define DDSD_PITCH 0x00000008 #define DDSD_PIXELFORMAT 0x00001000 #define DDSD_MIPMAPCOUNT 0x00020000 #define DDSD_LINEARSIZE 0x00080000 #define DDSD_DEPTH 0x00800000 #define DDPF_ALPHAPIXELS 0x00000001 #define DDPF_FOURCC 0x00000004 #define DDPF_RGB 0x00000040 #define DDSCAPS_COMPLEX 0x00000008 #define DDSCAPS_TEXTURE 0x00001000 #define DDSCAPS_MIPMAP 0x00400000 #define DDSCAPS2_CUBEMAP 0x00000200 #define DDSCAPS2_CUBEMAP_POSITIVEX 0x00000400 #define DDSCAPS2_CUBEMAP_NEGATIVEX 0x00000800 #define DDSCAPS2_CUBEMAP_POSITIVEY 0x00001000 #define DDSCAPS2_CUBEMAP_NEGATIVEY 0x00002000 #define DDSCAPS2_CUBEMAP_POSITIVEZ 0x00004000 #define DDSCAPS2_CUBEMAP_NEGATIVEZ 0x00008000 #define DDSCAPS2_VOLUME 0x00200000 int depth = 32; int width = 32; int height = 32; unsigned int header[32]; int main( int argc, char * argv[] ) { if( !argv[1] !strstr( argv[1], ".dds" ) ) { fprintf( stderr, "Usage: noise output.dds\n" ); return 1; } unsigned int cnt = width*height*depth*4; unsigned char * buf = new unsigned char[ cnt ]; while( cnt-- ) { buf[cnt] = rand()>>7; } memset( header, 0, sizeof( header ) ); header[0] = ' SDD'; header[1] = 124; header[2] = DDSD_CAPS | DDSD_PIXELFORMAT | DDSD_WIDTH | DDSD_HEIGHT | DDSD_DEPTH | DDSD_PITCH; header[3] = height; header[4] = width; header[5] = width*4; header[6] = depth; header[19] = 32; header[20] = DDPF_RGB|DDPF_ALPHAPIXELS; header[22] = 8; header[23] = 0xff0000; header[24] = 0xff00; header[25] = 0xff; header[26] = 0xff000000; header[27] = DDSCAPS_TEXTURE | DDSCAPS_COMPLEX; header[28] = DDSCAPS2_VOLUME; FILE * f = fopen( argv[1], "wb" ); if( !f ) { fprintf( stderr, "can't create: %s\n", argv[1] ); return 1; } fwrite( header, 4, 32, f ); fwrite( buf, 1, width*height*depth, f ); fclose( f ); fprintf( stderr, "wrote %s\n", argv[1] ); return 0; }
14 decimal in binary is 11102. In octal it is 168 and in hexadecimal it is 0E16.
No, binary is a number system.A binary digit is called a bit.
First let's write it as a sum of powers of two. This will make it easier to write as a binary number. 19=16+2+1 This can be written: 19=16*1+8*0+4*0+2*1+1*1 So the binary form is: 10011
No. In short, binary code is the code your computer executes, it can be in many forms, ranging from bytecode, which must be interpreted, but is pre-compiled to machine code, which is directly run by the system, and is generally specific to a particular system. Source code is the code of the program, as written by the programmer. It is written in a language that can be translated into instructions understood by computers. Most of the times, binary code is not easily human readable whereas source code is.
A 0 or 1 in a binary number is called a bit. A binary number is made up of only ones and zeroes.
Thirteen written in binary digits is: o|
The number 7 - written in binary is... 111
The number 11 in binary is 1011
Written in binary notation, it's 011010.Written in decimal notation, it's 26.
1010 is the number 10 represented in binary form.
4294967294 written in binary would be 11111111111111111111111111111110
The binary number 1101 equals 13
The cation is written first in the chemical formula for a binary ionic compound.
Binary numbers are written with two symbols, 0 and 1. It is not about counting by 2, any number can be written as a binary number, with the correct sequence of zeros and ones.
cg code for binary tree
231 written in binary numbers is 11100111
The number 200 written as a binary number is 11001000