yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle
A projectile leaving the ground at an angle of 45 degrees will attain the maximum range.
Fire it straight up and it will fall back to its launch location (wind effects etc. ignored).
Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.
What effect does angle have on the distance the projectile travels?
Given the initial velocity V, and the angle from the ground A, the total distance travelled X will be: X = 2 V2 cos(A) sin(A) / gwhere "g" is the acceleration due to gravity, on earth g is approximately 9.81 m/s2.You will notice that the mass of the object does not affect the distance traveled. We can derive this by first determining how long the projectile will be in the air. If the initial velocity is V, then the initial vertical velocity is Vsin(A). The vertical velocity will decrease at a rate of 'g' until the vertical velocity reaches zero (known as apogee), and the projectile starts falling down. The time from launch to apogee will be Vsin(A)/g.The time for the projectile to go up is the same as for the projectile to fall down again, so the total time in the airis 2Vsin(A)/g.Assuming we neglect friction, the horizontal velocity is Vcos(A) and does not change. The total distance traveled horizontally is the horizontal speed multiplied by the time spend in the air. So X = 2Vsin(A)/g * Vcos(A) = 2V2cos(A)sin(A)/g.The maximum distance is achived with an angle of 45o. The distance travelled is symmetric around this value, i.e. an angle of 50o will give the same distance as 40o, and an angle of 15owill give the same distance as 75o.
At 45° angle.
55
The half maximum range of a projectile is launched at an angle of 15 degree
yes it does the optimal ang
The optimal angle to fire a projectile if the objective is distance is 45 degrees. It follows that the distance traveled decreases whether the angle is increased or decreased from 45.
90
projection speed projection angle projection height
its 45 degree
The horizontal distance will be doubled.
The range of projectile is maximum when the angle of projection is 45 Degrees.
If you keep th velocity of projection and change the angle of projection from 75 degrees to 45 degrees what will happen to the horizontal distance the projectile travels? if you finish the nova net lesson you might learn the answer! It will travel a greater distance!
Do you really mean minimum distance? This would be achieved if the projectile went straight up and down, ie 90 deg from horizontal. Maximum distance would be obtained at 45 deg to horizontal.
A trajectory is the angle made with the horizontal when a projectile is fired. Suppose the projectile is a cannon ball. Assuming air is frictionless, that cannon ball will travel the greatest distance if the trajectory is 45 degrees from horizontal.
Given the initial velocity V, and the angle from the ground A, the total distance travelled X will be: X = 2 V2 cos(A) sin(A) / gwhere "g" is the acceleration due to gravity, on earth g is approximately 9.81 m/s2.You will notice that the mass of the object does not affect the distance traveled. We can derive this by first determining how long the projectile will be in the air. If the initial velocity is V, then the initial vertical velocity is Vsin(A). The vertical velocity will decrease at a rate of 'g' until the vertical velocity reaches zero (known as apogee), and the projectile starts falling down. The time from launch to apogee will be Vsin(A)/g.The time for the projectile to go up is the same as for the projectile to fall down again, so the total time in the airis 2Vsin(A)/g.Assuming we neglect friction, the horizontal velocity is Vcos(A) and does not change. The total distance traveled horizontally is the horizontal speed multiplied by the time spend in the air. So X = 2Vsin(A)/g * Vcos(A) = 2V2cos(A)sin(A)/g.The maximum distance is achived with an angle of 45o. The distance travelled is symmetric around this value, i.e. an angle of 50o will give the same distance as 40o, and an angle of 15owill give the same distance as 75o.
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
It affects the entire speed of the projectile is going to travel at. Shooting it at a higher initial velocity may increase the airtime of the projectile depending on the angle it was fired at.