Well compare a pendulum with swing. If the swing length is short, you will quickly return back to your middle position. Similarly
in a pendulum if you have a long string, the time take to complete one swing will be more. This means Time period is directly proportional to the increase in length . But by various experiments, they have found that T Is proportional to sq root of length.
T = 2pi sq root of (length /g)
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The period of a pendulum is given by the formula T = 2 * pi * sqrt(l / g),
where l is the length of the string, and g is about 9.81 m/s-2 .
A simple pendulum with a length of 45m has a period of 13.46 seconds. If the string is weightless, then the mass of the bob has no effect on the period, i.e. it doesn't matter.
No. Only the length of the string and the value of g does.
yes! it definitely depends on the length of the string.when the string is long it takes more time unlike when the string is short it takes lesser time........
The shorter the string - the faster the oscillation.
Yes. Period proportional to (Length)-2 is the fundamental property of the pendulum. The formula for the Period (1 complete swing), T, for a pendulum of length L is: T = 2*pi sqrt (L/g) (Oh for a library of symbols to avoid computer-code abbreviations!) T is in seconds, L in metres, g, the acceleration due to gravity, = 9.8m/s2 So for a given length, it is easy to work out the number of complete swings in 1 minute.
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
A simple pendulum with a length of 45m has a period of 13.46 seconds. If the string is weightless, then the mass of the bob has no effect on the period, i.e. it doesn't matter.
For a simple pendulum, consisting of a heavy mass suspended by a string with virtually no mass, and a small angle of oscillation, only the length of the pendulum and the force of gravity affect its period. t = 2*pi*sqrt(l/g) where t = time, l = length and g = acceleration due to gravity.
No. Only the length of the string and the value of g does.
yes! it definitely depends on the length of the string.when the string is long it takes more time unlike when the string is short it takes lesser time........
You mean the length? We can derive an expression for the period of oscillation as T = 2pi ./(l/g) Here l is the length of the pendulum. So as length is increased by 4 times then the period would increase by 2 times.
The shorter the string - the faster the oscillation.
The length of the pendulum is measured from the pendulum's point of suspension to the center of mass of its bob. Its amplitude is the string's angular displacement from its vertical or its equilibrium position.
There's no relationship between the length of the pendulum and the number of swings.However, a shorter pendulum has a shorter period, i.e. the swings come more often.So a short pendulum has more swings than a long pendulum has in the same amountof time.
The period of the pendulum can be influenced by the local magnitude of gravity, by the length of the string, and by the density of the material in the swinging rod (which influences the effective length).It's not affected by the weight of the bob, or by how far you pull it to the side before you let it go.
The mass of the pendulum, the length of string, and the initial displacement from the rest position.