acceleration cannot be calculated from these values alone unless one makes a few assumptions:
Vf=final velocity
Vi=initial velocity
a=acceleration
d=displacement
t=time
assume Vi=0
(Vf-Vi)/t=a
Vf=at+Vi
Vf**2=Vi**2+2ad
(at)**2=2ad
aatt=2ad
att=2d
a=2d/t**2
They are not alike but they are related. A positive acceleration means an increase in velocity (speed). A negative acceleration means a decrease in velocity. Velocity (speed) has the dimensions of distance / time. Acceleration has the dimensions of distance/time2 or velocity/time.
You mean how are they related? Sting from rest condition, let V = velocity, T = time, S = distance, A = acceleration V = AT S = 1/2 AT^2 If there is no acceleration, at constant velocity S = VT
Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.
There is no information that shows any relationship with time. Since acceleration is a variable related to time, it is impossible to answer the question.
it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.
Distance travelled or time elapsed between set points, given the speed at the first point. Also instantaneous speed.
For a free-falling object, you can calculate the total distance traveled, given the amount of time. The distance of the fall is proportional to the square of the time elapsed. In general, distance can be found by the relationship between acceleration and time squared. If we let a be acceleration, which can be gravity if you want, and t be time, then we have: The distance traveled = 1/2 * a * t2 The distance traveled = 1/2 * g* t2
Velocity is proportional to elapsed time when motion is in a straight line and acceleration is constant.
They are not alike but they are related. A positive acceleration means an increase in velocity (speed). A negative acceleration means a decrease in velocity. Velocity (speed) has the dimensions of distance / time. Acceleration has the dimensions of distance/time2 or velocity/time.
the distance x , the acceleration a and time of fall t are related int he following way: x = 1/2 a t ²
You mean how are they related? Sting from rest condition, let V = velocity, T = time, S = distance, A = acceleration V = AT S = 1/2 AT^2 If there is no acceleration, at constant velocity S = VT
Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.
Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity.
An acceleration is a velocity divided by a time, so you have: acceleration = velocity / time acceleration = (distance / time) / time acceleration = distance / time2 The gravitational field can also be expressed as force / mass; this is equivalent to distance / time2.
There is no information that shows any relationship with time. Since acceleration is a variable related to time, it is impossible to answer the question.
Acceleration= Distance divided by time
Divide distance travelled by elapsed time