React a solution of Copper(II) sulfate with Sodium Iodide. It will produce Copper(II) Iodide and Sodium sulfate. This Copper(II) iodide, due to instability, spontaneously decomposes, producing Iodine and Copper(I) Iodide.
The Copper(I) iodide comes out as a yellowish brown precipitate. So the overall reaction seems to be:
2 CuSO4 + 4 NaI ----> 2 CuI + 2 Na2SO4 + I2
Brownish white
I think it could be obtained by the single displacement rxn : K3I + Cu ---> K + Cu3I2
The correct spelling is 'cuprous', and means copper-conatining. Some cuprous metals are, copper (obviously), brass, and bronze
"Cuprous" is an archaic term for what today is called copper (I), Cu+1.
In the laboratory, copper(I) Iodide is prepared by simply mixing an aqueous solutions of potassium iodide and a soluble copper(II) salt such copper sulphate. : :: Cu2+ + 2I− → CuI2 The CuI2 immediately decomposes to iodine and insoluble copper(I) iodide, releasing I2. : :: 2 CuI2 → 2 CuI + I2
CuI
Brownish white
Formula: CuI
I think it could be obtained by the single displacement rxn : K3I + Cu ---> K + Cu3I2
in aqueous medium ppts. of copper iodide are formed which are converted into cuprous iodide and free iodine in a short time. 2NaI + Cu(NO3)2 = CuI2 + 2NaNO3 2CuI2 = Cu2I2 + I2
Francium iodide was not prepared but this compound should be real.Francium is very difficult to be prepared, unstable and because of the heat of decay is easy autovaporized - any experiment is possible.
The cuprous sulfide - Cu2S - is black.
The correct spelling is 'cuprous', and means copper-conatining. Some cuprous metals are, copper (obviously), brass, and bronze
Cuprous oxide or copper I oxide is Cu2O
a cuprous ion has 28 electrons.
"Cuprous" is an archaic term for what today is called copper (I), Cu+1.
In the laboratory, copper(I) Iodide is prepared by simply mixing an aqueous solutions of potassium iodide and a soluble copper(II) salt such copper sulphate. : :: Cu2+ + 2I− → CuI2 The CuI2 immediately decomposes to iodine and insoluble copper(I) iodide, releasing I2. : :: 2 CuI2 → 2 CuI + I2