For a single phase 3 HP motor at 208 volts the amperage is 18.7 amps. For a three phase 3 HP motor at 208 volts the amperage is 10.5 amps. This figure is derived at by taking the full load amps at 230 volts and adding 10%. As the voltage goes down the amperage goes up. For 200 volt motors 15% is added to the FLA of a 230 volt motor.
To calculate watts, you need to multiply the voltage (in volts) by the current (in amps). For the 208 volts, 8 amps heating element: Watts = 208 volts * 8 amps = 1664 watts For the 110 volts, 8 amps heating element: Watts = 110 volts * 8 amps = 880 watts
One Megawatt = 1,000,000 watts. Watts = Volts x Amps or voltage x current. Hence if you know the voltage then Amps = 1,000,000 watts / Volts.
I am assuming that you are talking single phase. 45 kva is k = 1000, v = volts, a = amps. 45 kva is 45000 volt / amps. Input 45000 divided by 208 volts = 216 amps. Output 45000 divided by 120 volts = 375 amps. There are other losses in the transformer but as a general rule of thumb this is the calculation that you would use.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
The watts is the volts times the amps So 208 x 50 watts, or 10.4 kW.
To calculate watts, you need to multiply the voltage (in volts) by the current (in amps). For the 208 volts, 8 amps heating element: Watts = 208 volts * 8 amps = 1664 watts For the 110 volts, 8 amps heating element: Watts = 110 volts * 8 amps = 880 watts
One Megawatt = 1,000,000 watts. Watts = Volts x Amps or voltage x current. Hence if you know the voltage then Amps = 1,000,000 watts / Volts.
#8 copper
I am assuming that you are talking single phase. 45 kva is k = 1000, v = volts, a = amps. 45 kva is 45000 volt / amps. Input 45000 divided by 208 volts = 216 amps. Output 45000 divided by 120 volts = 375 amps. There are other losses in the transformer but as a general rule of thumb this is the calculation that you would use.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
The watts is the volts times the amps So 208 x 50 watts, or 10.4 kW.
If you have 208 between legs, you have 120 from each leg to neutral (208 divided by 1.73). Assuming a balanced load, this would be 1 KW per leg - 1000 divided by 120 = 8.33 amps per leg. Your question contradicts itself. If you have 208v, the answer above is correct, 8.33 amps. If you have 480v, you have 3.6 amps.
1,040 watts or 1.04 KW.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
To convert amps to kVA, you use the following formula: Amps = (kVA x 1000 / voltage) / 1.73
I am assuming that you have just moved into a new apartment building. Commercial building power systems are changing to 3 phase. The 3 phase voltages are 120/208. 240 volt equipment will run on 208 voltages but at a reduced wattage output. For example Watts = amps x volts. Say your dryer draws 20 amps x 240 volts = 4800 watts. Now at reduced voltage, 20 amps x 208 volts = 4160 watts. As you can see your dryer won't get as hot and will take longer to dry. Most apartments that come with appliances will be rated at 208 volts. See what your dryer manufacturer has to say about getting around the Power failure alarm or whether it can be bypassed to operate on the lower voltage. Other option is to sell the 240 volt dryer and buy a 208 volt dryer. at 208 volts it will not draw 20 amps either
I bought a 208 cc snowblower , how many horsepower is that ?