Long answer: It depends on the temperature of the water you start with. Before you can evaporate the water, you must heat it to it's boiling point. The warmer the water you start with the fewer BTUs will be needed to heat the water to its boiling point. Keep in mind the BTUs require to raise the water to its boiling point are very few compared to the BTUs required to change the water from a liquid to a gas.
One pound of steam contains 1150 BTUs. This is the energy you need to put into the water for it to evaporate if you start with water at 32F. If you start with water at 100F the water already has 70 BTU/lb so the BTUs required to evaporate the water when you start at 100F is 1150-70 = 1080 BTU and so on.
You can get all this information in a steam table which can be found easily by searching the web.
Any amount of heat will evaporate water, it just takes longer with less heat.
I'm leaving the above answer to illustrate a common misunderstanding. "Heat" in chemistry and physics has a specific meaning that may be different from what most people mean by heal.
The specific heat of vaporization of water is about 2250 kJ per kilogram. This is quite close to 1 megajoule (1000 kJ) per pound.
Quick Answer: About 2,139 BTU/litre at the normal boiling point.
Long answer: It depends on the temperature and pressure of the water you start with. Before you can evaporate the water, you must heat it to it's boiling point. The warmer the water you start with the fewer BTUs will be needed to heat the water to its boiling point. Keep in mind the BTUs require to raise the water to its boiling point are very few compared to the BTUs required to change the water from a liquid to a gas.
One litre of water weighs about 2.205 lb, and since both BTUs and lb are from the imperial set of units, we can make the rest of this explanation in terms of pounds and then just multiply by 2.205 when we get done.
One pound of steam contains 1150 BTU/lb relative to liquid water at 32 °F. This is the energy you need to put into the water for it to evaporate if you start with water at 32 °F. If you start with water at 100 °F the water already has 70 BTU/lb so the BTUs required to evaporate the water when you start at 100 °F is 1150-70 = 1080 BTU/lb and so on.
You can get all this information in a steam table which can be found easily by searching the web.
The water heat of vaporization is 40,65 kJ/mol.
2000
There are 1078.9 BTUs.
On average it takes about 1,600 BTUs to heat 50 square feet. Multiplying 50 by 1600 equals about 80,000. Therefore, the heating plan of 1,600 square foot are would take about 80,000 BTUs.
1MW = 1000 KW 1KW = 860 Kcal/Hour 1 Kcal = 3.968 BTu.
1 gal of #2 fuel oil (or diesel for that matter) has an equivalent of 115,000 BTUS. I say equivalent because it has a little more than that raw (like 136k or so) but the furnace that burns it is only around 85% efficient, therefore you only get 115K BTUS.
A 100 pound propane tank has a capacity of 2,160,509 BTUs
144
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
One million.
212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
actually its 313.
313 Btu
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
Many liquids evaporate, one example is water
1320 btu`s