You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
A BTU is the amount of heat required to heat or cool 1 lb of water 1 degree, water freezes at 32F so it should not require any more than 1 degree to be below freezing.
There are 8lbs in1 gallon of water, so 8 BTU's will lower a gallon(8 lbs) 1 degree.
6,520 Btus
That will completely depend on how much water there is.
2250
313 Btu
Depends on the BTUs of the heater.
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
6,520 Btus
That will completely depend on how much water there is.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
25
2250
About 114,000 BTU per US gallon.
313 Btu
100 BTU if it's Fahrenheit
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!
One gallon of kerosene will produce 134,000 BTUs of energy when burned.
1 BTU = heat corresponding to change in temperature of 1 pound of water by 1° Fahrenheit.Weight of 1 gallon of water = roughly 8.33 poundsHeat corresponding to change in temperature of 1 gallon of water by 1° Fahrenheit = 8.33 BTU.But it doesn't take that, i.e. you don't have to supply it. You're talking about lowering thetemperature, so you're just allowing the water to cool on its own. As it does, it releases8.33 BTU of heat, which you can then collect and take away to use somewhere else.