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The gram Atomic Mass of carbon is 12.011. Therefore, 1.1 grams constitutes 1.1/12.011 or about 0.0908 moles of carbon. The number of atoms is then 0.0908 X Avogadro's Number or 5.5 X 1022 atoms, to the justified number of significant digits.

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12y ago
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14y ago

5.02 x 10^23 atoms C

I arrived at this answer by setting up a conversion factor, using Avogardro's number (6.022x10^23) and the atomic mass of Carbon rounded to the nearest whole number (12g). I then rounded my own answer to maintain the 3 significant figures of 10.0. When you do so you arrive at this equation:

10.0g C X (1mol C/ 12 g C) X (6.022x10^23/ 1 mol C) = 5.02 x 10^23 atoms C

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14y ago

no.moles of carbon = mass/relitive molecular mass = 10/12 = 0.833

no atoms in a mole = 6.022 x 1023, and we have 0.833 of a mole = 5.0183 x 1023 atoms in 10g of carbon.

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9y ago

12.0107 amu (not grams)

It is just larger than 12 due to a small amount of carbon-13 in natural carbon.

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Q: How many atoms of carbon are in 10.0 grams of carbon?
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