Just one.* * * * *Depends on how many numbers are on each ring. If there are x numbers, then the total number of combinations (actually they are permutations) is x*x*x or x3.
I'm assuming they're three unique numbers. Thus, the first can be any of three, the second either of the remaining two, and the last is the last one left. Thus: combinations = 3 * 2 * 1 = 6 Or, more...