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Since water vapor is a gas, it depends on the Pressure and Temperature. The ideal gas law can be used for a given pressure and temperature. PV = nRT
Assuming 1 atmosphere pressure, and 100°C temperature (like the water had just boiled and turned to vapor, this can be computed. Note that water vapor can exist at a range of temperatures, not just above the boiling point. But at other temperatures, it will be mixed with the air (humidity).
1 pound = 453.59 grams. The Atomic Mass of H2O is 18 grams/mole, so 453.59 grams / (18 grams/mole) = 25.2 moles.
R is the ideal gas constant = 8.314472 Joule/Kelvin/mole. (SI units)
T of 100°C is 373 Kelvin. 1 atmosphere = 101325 pascals (SI unit equivalent to Joule/meter3).
Substituting these in and isolating V = 0.77129 cubic meters = 27.24 cubic feet.
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How many cubic feet of steam do you get when you boil 1 gallon of water?
Based on the calculations in the related question (How many cubic feet of water vapor equals 1 pound?) using the Ideal Gas Law, 1 pound of water will be 27.24 cubic feet at 1 atmosphere pressure and 100°C (212°F).1 gallon of water is 8.3454 pounds, so at the temperature 212°F and 1 atmosphere pressure, 1 gallon will generate 227.33 cubic feet.
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