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How many different combinations of four with six numbers if you can't repeat the numbers?
Wiki User
∙ 15y ago
The answer depends on whether order matters. For example, would 1234 be considered the same as 4321. If order does not matter, there are only 15 combinations. This answer was obtained dividing the factorial 6 by the product of the factorial of 4 and the factorial of (6-4). In general, the amount of unordered combinations of x with y numbers is equal to y!/(x!(y-x)!). If order does matter, there are 360 combinations. This answer was obtained by diving the factorial of 6 by the factorial of (6-4). In general, the amount of ordered combinations of x with y numbers is equal to y!/((y-x)!).
Wiki User
∙ 15y ago
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How many place combinations in a four digit number and all have to go in diff spots eg 1234 4321 2134 etc numbers cant change and have to stay same four numbers?
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
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