The number of grams in a mole of a molecule is found by looking at the Atomic Mass of each element on the Periodic Table. The molar mass of an element is it's atomic mass in grams. The atomic mass of oxygen is 15.999. Since there are two atoms of oxygen in a molecule of oxygen, the molar mass of oxgen (O2) is 15.999 x 2. That comes out to 31.998g/mol, or you can round to 32 if significant figures arn't important to you.
A mole is the measument of a single, in this case oxygen molecule. Oxygen on the periodic table is shown like this 8 O 16.00 The 16 is showing the atomic mass. So to answer the question above the answer is ... There are 1,600 moles in 100 grams of oxygen
Oxygen at standard temperature and pressure exists as diatomic molecules. Therefore, the gram molecular mass of oxygen gas is twice the atomic mass of oxygen, or about 32 grams. Therefore, 32 g of oxygen gas constitutes 1.0 moles of oxygen, to the justified number of significant digits.
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.
2.00 moles O2 × (32.0 grams) = 64.0 grams O2
100 grams O2 (1mol O2/32g)(6.022 X 10^23/1mol O2 ) = 1.88 X 10^24 molecules
32 in O2 and 16 in O
6.25
0.03125
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
using the equation moles=mass/molar mass (since its in gas form) O2 => 16*2 =32 0.16/32=0.005 moles :)
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : mass = Mr x number of moles mass = 32g/mol x 50mols = 1600g
The answer is 0,173 moles.
The answer is 0,8 moles oxygen.
6,5 moles oxygen equals 208 g.
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
The equivalent in moles is 6,03.
The answer is 2 moles.
Mass of Hydrogen gas:- 2g/mol Mass of Oxygen gas :- 32g/mol Therefore, Oxygen gas is more heavier
The mass of 0,2 moles of oxygen gas is 6,4 g.
Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).
1 mole.
3.058